Question

我正在尝试创建一个小型计算器小部件但我无法使用StringBuilder连接输入字符串，因为按钮上每次单击时的小部件仅显示与单击的按钮对应的字符串。

似乎StringBuilder中的追加方法无效。你能给我一些帮助吗？

以下是代码的相关部分：

StringBuilder sb  = new StringBuilder();
@Override
public void onReceive(Context context, Intent intent) {
    final String action = intent.getAction();

    Log.i(LOG_TAG, "onReceive(): " + action);
    if (ACTION_WIDGET_CONTROL.equals(action)) {
        final int appWidgetId = intent.getIntExtra(
                AppWidgetManager.EXTRA_APPWIDGET_ID,
                AppWidgetManager.INVALID_APPWIDGET_ID);
        if (appWidgetId != AppWidgetManager.INVALID_APPWIDGET_ID) {
            fnHandleCommand(context, intent, appWidgetId);
        }
    } else {
        super.onReceive(context, intent);
    }
}

private void fnHandleCommand(Context context, Intent intent, int appWidgetId) {
    int control_id = intent.getIntExtra(COMMAND, -1);

    switch (control_id) {
    case R.id.Button00:
        String zero = "0";
        sb.append(zero);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button01:
        String uno = "1";
        sb.append(uno);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button02:
        String due = "2";
        sb.append(due);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button03:
        String tre = "3";
        sb.append(tre);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button04:
        String quattro = "4";
        sb.append(quattro);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button05:
        String cinque = "5";
        sb.append(cinque);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button06:
        String sei = "6";
        sb.append(sei);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button07:
        String sette = "7";
        sb.append(sette);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button08:
        String otto = "8";
        sb.append(otto);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.Button09:
        String nove = "9";
        sb.append(nove);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.ButtonPlus:
        String piu = "+";
        sb.append(piu);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.ButtonMinus:
        String meno = "-";
        sb.append(meno);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.ButtonMutiple:
        String per = "*";
        sb.append(per);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.ButtonDivide:
        String diviso = "/";
        sb.append(diviso);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.ButtonNegative:
        String rad = "\u221a";
        sb.append(rad);
        setInputText(context, appWidgetId,sb.toString());
        break;
    case R.id.ButtonAC: 
        String vuota = "";
        sb.setLength(0);
        cancel(context, appWidgetId,sb.toString(),vuota);
        break;
    default:
        break;
    }
    fnVibrate(context);
}

private void setInputText(Context context, int appWidgetId, String value) {
    RemoteViews remoteView = new RemoteViews(context.getPackageName(),
            R.layout.simple_calculator);
    remoteView.setTextViewText(R.id.TextValue, value);
    AppWidgetManager.getInstance(context).updateAppWidget(appWidgetId,
            remoteView);
}

由于

Answer 1

private static StringBuilder sb = new StringBuilder（）;

Append方法在StringBuilder中不起作用

1 个答案: