我无法在地图上显示圆圈,但我没有收到任何错误。谁能告诉我我做错了什么,拜托?
function initialize() {
var mapOptions = {
center: new google.maps.LatLng(41.0342375, -77.3066405),
zoom: 8,
mapTypeControl: false,
mapTypeId: google.maps.MapTypeId.TERRAIN, //style below will be 'shift worker' from snazzy maps
styles: [{"stylers":[{"saturation":-100},{"gamma":1}]},{"elementType":"labels.text.stroke","stylers":[{"visibility":"off"}]},{"featureType":"poi.business","elementType":"labels.text","stylers":[{"visibility":"off"}]},{"featureType":"poi.business","elementType":"labels.icon","stylers":[{"visibility":"off"}]},{"featureType":"poi.place_of_worship","elementType":"labels.text","stylers":[{"visibility":"off"}]},{"featureType":"poi.place_of_worship","elementType":"labels.icon","stylers":[{"visibility":"off"}]},{"featureType":"road","elementType":"geometry","stylers":[{"visibility":"simplified"}]},{"featureType":"water","stylers":[{"visibility":"on"},{"saturation":50},{"gamma":0},{"hue":"#50a5d1"}]},{"featureType":"administrative.neighborhood","elementType":"labels.text.fill","stylers":[{"color":"#333333"}]},{"featureType":"road.local","elementType":"labels.text","stylers":[{"weight":0.5},{"color":"#333333"}]},{"featureType":"transit.station","elementType":"labels.icon","stylers":[{"gamma":1},{"saturation":50}]}]
};
var mymap = new google.maps.Map(document.getElementById("map-canvas"), mapOptions);
}
var map = document.getElementById("map-canvas");
$(document).ready(function() {
google.maps.visualRefresh = true;
google.maps.event.addDomListener(window, 'load', initialize);
var populationOptions = {
strokeColor: '#FF0000',
strokeOpacity: 0.8,
strokeWeight: 2,
fillColor: '#FF0000',
fillOpacity: 0.35,
map: map,
center: new google.maps.LatLng(41.0342375, -77.3066405),
radius: 84482
};
// Add the circle for this city to the map.
cityCircle = new google.maps.Circle(populationOptions);
});
答案 0 :(得分:2)
Javascript中的变量范围位。
mymap
变量是您需要用于CircleOptions map
属性的变量。但是它的初始化功能超出了范围。匿名函数中的map
变量只是一个DIV DOM元素,而不是google.maps.Map
实例。
简化工作示例@ http://jsfiddle.net/stevejansen/H5bRg/
没有理由将jQuery的文档#ready事件处理程序与google.maps.event.addDomListener(window, 'load', initialize);
结合起来。它们都处理相同的DOM事件。坚持一个或另一个。使用两者都很困惑。