Question

我是Ruby on Rails的新手，我不会根据它的数量改变一个单词的结尾。

接近下面代码的顶部，你会看到我写的

h3 "The deal has #{deal.prizes.where(:prize_type => u).count} #{u}

这里的“u”表示名为PRIZE_TYPE的数组中的一个值。我怎么能这样做

如果count = 1，则显示“该交易有1个累积奖金”
如果count = 4，则显示“该交易有4个累积奖金

注意：计数不能是= 0或＆lt; 0

这是我的代码：

panel "Details of Prizes" do

      PRIZE_TYPES.each do |u|

        table_for deal.prizes.where(:prize_type => u) do |t|
          h3 "The deal has #{deal.prizes.where(:prize_type => u).count} #{u}s
          initially set in the campaign for a total value of #{custom_number_to_currency (deal.category_prizes_total_initial_value(u)) }", class: 'title-within-table'
          if deal.prizes.where(:prize_type => u).count > 0 # if there is at least one record of 'jackpot prize'
            t.column("Prize")             { |prize| link_to( image_tag( prize.prize_image_url, class: 'main_img_in_admin_interface' ), admin_prize_path(prize), target: :blank ) }
            t.column("Name")              { |prize| link_to prize.prize_name, admin_prize_path(prize), target: :blank }
            t.column("Category")          { |prize| prize.prize_category }
            t.column("Initial quantity")  { |prize| prize.prize_initial_stock_quantity }

      end # end of Prize.each...

    end # end of panel "details of prizes"

PRIZE_TYPE常量：

PRIZE_TYPES = ["Jackpot prize","Consolation prize", "awesome prize"]

Answer 1

你可以使用ruby的复数：

prize_type.pluralize(count)
"Jackpot prize".pluralize(1)
#> Jackpot prize
"Jackpot prize".pluralize(2)
#> Jackpot prizes

或ActiveSupport::Inflector.pluralize如果您想自己检查一下：

prize_type.pluralize
"Jackpot prize".pluralize
#> "Jackpot Prizes"

或者rails具有使用组合Inflector和一些基本逻辑的复数：

pluralize(count, prize_type)
pluralize(1, prize_type)
#> 1 Jackpot prize
pluralize(2, prize_type)
#> 2 Jackpot prizes

Answer 2

您可以使用ruby实例方法

http://apidock.com/rails/ActionView/Helpers/TextHelper/pluralize

"string".pluralize(count)

所以对你的情况来说，

prizes_count = deal.prizes.where(prize_type: u).count
h3 "The deal has #{prizes_count} #{u.pluralize(prizes_count)}"

Answer 3

使用pluralize

count = deal.prizes.where(:prize_type => u).count
h3 "The deal has #{count} #{u.pluralize(count)}}"

Answer 4

根据pluralize

您可以做

pluralize(1, 'person')
# => 1 person

pluralize(2, 'person')
# => 2 people

pluralize(3, 'person', plural: 'users')
# => 3 users

pluralize(0, 'person')
# => 0 people

pluralize(2, 'Person', locale: :de)
# => 2 Personen

Ruby：如何根据可变数量在Active Admin面板中复数/单个化单词（Active Admin，rails 3.2，ruby）

4 个答案: