Question

所以这个方法的目的是得到一个高于100的温度数组。这有什么问题？当我在toString中返回它时，它说blazing []不存在。

public int[] above100Degrees()
   {
      int[] blazing = new int[temps.length];
      for( int i = 0; i < temps.length; i++ )
      {
         if( temps[i] > 100 )
         {
            blazing[i] = temps[i];
         }
      }
      return blazing;
   }

toString方法：

 public String toString()
    {
      String returnString = "The temperature forecast of week " + WEEK + " is logged in as: ";
      for( int i = 0; i < temps.length; i++ )
      {
          returnString += "\t" + temps[i] + "\t";
      }
      returnString += "\n" + "The number of temperatures below freezing is " + getUnderFreeze() + "." + "\n" + 
                             "The largest difference this week was a net change of " + NetChange() + "."; 
      for( int i = 0; i < blazing.length; i++ )
      {
         returnString += "The temperature above 100 degrees is " + above100Degrees() + "." + "\n" + "\t" + blazing[i] + "\t";
      }
      return returnString;
    }

输出

Forecast.java:122: error: cannot find symbol
      for( int i = 0; i < blazing.length; i++ )
                          ^
  symbol:   variable blazing
  location: class Forecast
Forecast.java:124: error: cannot find symbol
         returnString += "The temperature above 100 degrees is " + above100Degrees() + "." + "\n" + "\t" + blazing[i] + "\t";
                                                                                                           ^
  symbol:   variable blazing
  location: class Forecast
2 errors

Answer 1

数组由above100Degrees方法返回。它不会在调用它的范围内建立变量名blazing。实际上，您可以将返回的数组分配给名为different的变量。

尝试

int[] reallyHot = above100Degrees();
// Then check reallyHot...
for( int i = 0; i < reallyHot.length; i++ )
{
     returnString += "The temperature above 100 degrees is " + reallyHot[i] + "." + "\n";
}

确保使用数组访问语法访问特定元素。

Answer 2

更改：

for( int i = 0; i < blazing.length; i++ )
{
    returnString += "The temperature above 100 degrees is " + above100Degrees() + "." + "\n" + "\t" + blazing[i] + "\t";
}

到：

int[] blazing = above100Degrees();
for( int i = 0; i < blazing.length; i++ )
{
    returnString += "The temperature above 100 degrees is " + blazing[i] + "."; // personalise format
}

Answer 3

你的above100Degrees（）函数返回数组blazing，但是你没有在toString（）方法中调用该函数。就toString（）而言，不存在炽热。

从toString（）中调用above100Degrees（）并将结果数组保存到变量中。然后你就可以迭代（newVariable）.length而不是blazing.length。

逻辑不正确

3 个答案: