Question

我正在尝试为“输入秒数”编写一个python脚本，并以周，天，小时，分钟和秒为单位获得结果。这是我的，但我没有得到正确的答案。我做错了什么？

seconds = raw_input("Enter the number of seconds:")
seconds = int(seconds)

minutes = seconds/60

seconds = seconds % 60

hours = minutes/60
hours = seconds/3600

minutes = minutes % 60

days = hours/24
days= minutes/1440
days = seconds/86400

hours = hours % 60
hours = minutes % 60
hours = seconds % 3600

weeks = days/7
weeks = hours/168
weeks = minutes/10080
weeks = seconds/604800

days = days % 1
days = hours % 24
days = minutes % 1440
days = seconds % 86400

weeks = weeks % 1
weeks = days % 7
weeks = hours % 168
weeks = minutes % 10080
weeks = seconds % 604800

print weeks, 'weeks', days, 'days', hours, 'hours', minutes, 'minutes', seconds, 'seconds'

Answer 1

仅从基本转换原则：

weeks = seconds / (7*24*60*60)
days = seconds / (24*60*60) - 7*weeks
hours = seconds / (60*60) - 7*24*weeks - 24*days
minutes = seconds / 60 - 7*24*60*weeks - 24*60*days - 60*hours
seconds = seconds - 7*24*60*60*weeks - 24*60*60*days - 60*60*hours - 60*minutes

做同样事情的一点点吵闹的方式：

weeks = seconds / (7*24*60*60)
seconds -= weeks*7*24*60*60
days = seconds / (24*60*60)
seconds -= days*24*60*60
hours = seconds / (60*60)
seconds -= hours*60*60
minutes = seconds / 60
seconds -= minutes *60

同样具有divmod函数的更清晰版本，它在元组(division, remainder)中返回除法结果和余数：

weeks, seconds = divmod(seconds, 7*24*60*60)
days, seconds = divmod(seconds, 24*60*60)
hours, seconds = divmod(seconds, 60*60)
minutes, seconds = divmod(seconds, 60)

基本上，此解决方案最接近您的尝试，因为这是divmod所做的：

weeks, seconds = divmod(seconds, 7*24*60*60)

相当于

weeks = seconds / (7*24*60*60)
seconds = seconds % (7*24*60*60)

在这里，我们基本上可以找到我们这个星期的整周数，并保留这几周后剩下的数量。

而且你也可以从另一端走，使它更漂亮：

minutes, seconds = divmod(seconds, 60)
hours, minutes = divmod(minutes, 60)
days, hours = divmod(hours, 24)
weeks, days = divmod(days, 7)

这背后的想法是你的答案中的秒数是以分钟为单位除以后的余数;分钟是将所有分钟分成小时等的剩余时间......此版本更好，因为您可以轻松地将其调整为数月，数年等...

Answer 2

使用python datetime timedeltas支持毫秒或微秒。

import datetime
def convert(sec): 
    td = datetime.timedelta(seconds=sec, microseconds=sec-int(sec)) 
    return td.days/7, (td.days/7)%7, td.seconds/3600, (td.seconds/60)%60, td.seconds%60, td.microseconds, td.microseconds/1000

seconds = 8*24*60*60+21627.123  # 8 days, 6 hours (21600 seconds), 27.123 seconds
w,d,h,m,s,us,ms = convert(seconds)
print '{}s / {}w {}d {}h {}m {}s {}us {}ms'.format(seconds,w,d,h,m,s,us,ms)

712827.123s / 1w 1d 6h 0m 27s 123000us 123ms

Answer 3

def humanize_duration(amount, units='s'):
INTERVALS = [(lambda mlsec:divmod(mlsec, 1000), 'ms'),
             (lambda seconds:divmod(seconds, 60), 's'),
             (lambda minutes:divmod(minutes, 60), 'm'),
             (lambda hours:divmod(hours, 24), 'h'),
             (lambda days:divmod(days, 7), 'D'),
             (lambda weeks:divmod(weeks, 4), 'W'),
             (lambda years:divmod(years, 12), 'M'),
             (lambda decades:divmod(decades, 10), 'Y')]

for index_start, (interval, unit) in enumerate(INTERVALS):
    if unit == units:
        break

amount_abrev = []
last_index = 0
amount_temp = amount
for index, (formula, abrev) in enumerate(INTERVALS[index_start: len(INTERVALS)]):
    divmod_result = formula(amount_temp)
    amount_temp = divmod_result[0]
    amount_abrev.append((divmod_result[1], abrev))
    if divmod_result[1] > 0:
        last_index = index
amount_abrev_partial = amount_abrev[0: last_index + 1]
amount_abrev_partial.reverse()

final_string = ''
for amount, abrev in amount_abrev_partial:
    final_string += str(amount) + abrev + ' '
return final_string

在python中将秒转换为周 - 日 - 小时 - 分 - 秒

3 个答案: