b)将以下switch语句转换为if ... else语句。
#include <stdio.h>
void main()
{
char option;
int a;
printf("a.Addition\n b.Subtraction\n c.Multiplication\n d.Division\n");
printf("Choose your option : ");
scanf("%c",&option);
switch(option)
{
case 'a':
case 'A': a=20+10;
printf("Addition process result:%d",a);
break;
case 'b':
case 'B': a=20-10;
printf("Subtraction process result:%d",a);
break;
case 'c':
case 'C': a=20*10;
printf("Multiplication process result:%d",a);
break;
case 'd':
case 'D': a=20/10;
printf("Division process result:%d",a);
break;
default: printf("Invalid option");
}
printf("\nEnd of program");
}
如何将它从SWITCH转换为IF ... ELSE? 这是我考试的修订问题 谢谢
答案 0 :(得分:6)
switch
语句可以被视为一系列if
/ else
条款。这是一个可以帮助您解决特定问题的示例:
switch (x)
{
case 1:
case 2:
foo();
break;
case 3:
case 4:
bar();
break;
default:
blech();
break;
}
变为:
if (x == 1 || x == 2) // case 1:
{ // case 2:
foo();
}
else if (x == 3 || x == 4) // case 3:
{ // case 4:
bar();
}
else // default:
{
blech();
}
答案 1 :(得分:1)
if(option == 'a' ||option == 'A') //checks if option value is 'a' or 'A',in switch case you use case:a,and case:b
{
a=20+10;
printf("Addition process result:%d",a);
}
else if(option == 'b' ||option == 'B')
{
a=20-10;
printf("Subtraction process result:%d",a);
}
else if(option == 'c' ||option == 'C')
{
a=20*10;
printf("Multiplication process result:%d",a);
}
else if(option == 'd' ||option == 'D')
{
a=20/10;
printf("Division process result:%d",a);
}
else
{
printf("Invalid option");
}
我是如何转型的:
1:将所有cases
更改为if
示例:
switch(option)
{
case 'a':
case 'A':some statement;
break;
}
到
if(option == 'a' || option == 'A')
{
some statement;
}
答案 2 :(得分:0)
#include <stdio.h>
void main()
{
char option;
int a;
printf("a.Addition\n b.Subtraction\n c.Multiplication\n d.Division\n");
printf("Choose your option : ");
scanf("%c",&option);
if (option == 'a' || option == 'A') {
printf("Addition process result:%d",a);
}
elseif (option == 'b' || option == 'B') {
printf("Subtraction process result:%d",a);
}
elseif (option == 'c' || option == 'C') {
printf("Multiplication process result:%d",a);
}
elseif (option == 'd' || option == 'D') {
printf("Division process result:%d",a);
}
else {
printf("Invalid option");
}
printf("\nEnd of program");
}
这是你问题的解决方案。