JNLP Parse异常

Question

我在尝试启动applet时在java控制台中看到以下错误。我们正在运行Apache 2.2和WebSphere应用程序服务器7.0.0.27。有什么指针吗？

JNLParseException[ Could not parse launch file. Error at line 26.]
    at com.sun.javaws.jnl.XMLFormat.throwNewException(Unknown Source)
    at com.sun.javaws.jnl.XMLFormat.parse(Unknown Source)
    at com.sun.javaws.jnl.LaunchDescFactory.buildDescriptor(Unknown Source)
    at com.sun.javaws.jnl.LaunchDescFactory.buildDescriptor(Unknown Source)
    at com.sun.javaws.jnl.LaunchDescFactory.buildDescriptorFromCache(Unknown Source)
    at com.sun.javaws.jnl.LaunchDescFactory.buildDescriptorFromCache(Unknown Source)
    at sun.plugin2.applet.JNLP2Manager.initialize(Unknown Source)
    at sun.plugin2.main.client.PluginMain.initManager(Unknown Source)
    at sun.plugin2.main.client.PluginMain.access$300(Unknown Source)
    at sun.plugin2.main.client.PluginMain$2.run(Unknown Source)
    at java.lang.Thread.run(Unknown Source)
Error while initializing manager: JNLParseException[ Could not parse launch file. Error at line 26.], bail out

Answer 1

有一个用于检查jnlp错误的简洁工具：JaNeLA（可在share drive上找到）。

Answer 2

根据Exception，您的jnlp文件中存在XML语法错误。

您可以使用XML编辑器验证文件（XML Copy Editor）。您也可以将JNLP文件放在您的问题中。