Question

我正在尝试在提交表单时调用JavaScript函数。

这是代码，但在提交未调用的函数时，请提出建议并且我想使用javascript方法显示错误消息，如何在使用JavaScript的验证中显示错误消息。

<form id="register" name="register"  onsubmit="validateForm()">
<label for="Username"> Username </label><br>
<input type="text" class="register-control" id="Username" name="Username" placeholder="Enter Username"> <br><br>
<label for="Password"> Password </label><br>
<input type="password" class="register-control" id="Password" name="Password" placeholder="Enter Password"><br><br>
<label for="Confirm-Password"> Confirm Password </label><br>
<input type="password" class="register-control" id="Confirm-Password" name="Confirm-Password" placeholder="Confirm Password" ><br><br>

<label for="email"> Email </label><br>
<input type="email" class="register-control" id="email" name="email" placeholder="Enter Valid Email"><br><br>
<button type="submit">Submit</button>

</form>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js"></script>
 <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.8/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
    $("#register").validate({
        rules: {
            "Username": {
                required: true,
            },
            "Password": {
                required: true,
                minlength: 5
            },
            "Confirm-Password": {
                required: true,
            },
            "email": {
                required: true,
            }
        }
    });
});
</script>

这是JavaScript代码

function validateForm()
{
    var password = document.forms["register"]["Password"].value;
    var con-password = document.forms["register"]["Confirm-Password"].value;
    if(password != con-password)
    {
        document.getElementById('password-error').style.visibility='visible';
        alert("not matched");
    }
    alert("matched");
}

Answer 1

这可能是由于脚本中存在语法错误。当您看到类似的错误时，请查看浏览器的JavaScript控制台。

在这种情况下，con-password不是有效的变量名称。 JavaScript看到的是：

var con - password ...

即。代码显示“来自password的减去con”。请尝试使用下划线：

var con_password ...

Answer 2

不需要为密码匹配做任何额外的事情，只需向其添加equalTo: "#Password"，如下例所示：

$(document).ready(function () {
    $("#register").validate({
        rules: {
            "Username": {
                required: true,
            },
            "Password": {
                required: true,
                minlength: 5
            },
            "Confirm-Password": {
                required: true,
                equalTo: "#Password"
            },
            "email": {
                required: true,
            }
        },
       messages: {
         Password: {
                    required: "Please provide a password",
                    minlength: "Your password must be at least 5 characters long"
                    },
         Confirm-Password: {
                    required: "Please provide a confirm password",
                    equalTo: "Please enter the same password as above"
                    }
        },
        submitHandler: function(form) { 
            // Your function call  
            return false; // return true will submit form
            }
    });
});

工作示例：

<form id="register" name="register" action="" method="post">
<label for="Username"> Username </label><br>
<input type="text" class="register-control" id="Username" name="Username" placeholder="Enter Username"> <br><br>
<label for="Password"> Password </label><br>
<input type="password" class="register-control" id="Password" name="Password" placeholder="Enter Password"><br><br>
<label for="Confirm-Password"> Confirm Password </label><br>
<input type="password" class="register-control" id="Confirm_Password" name="Confirm_Password" placeholder="Confirm Password" ><br><br>

<label for="email"> Email </label><br>
<input type="email" class="register-control" id="email" name="email" placeholder="Enter Valid Email"><br><br>
<button type="submit">Submit</button>

</form>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js"></script>
 <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.8/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
    $("#register").validate({
        rules: {
            "Username": {
                required: true,
            },
            "Password": {
                required: true,
                minlength: 5
            },
            "Confirm_Password": {
                required: true,
                equalTo: "#Password"
            },
            "email": {
                required: true,
            }
        },
       messages: {
         Password: {
                    required: "Please provide a password",
                    minlength: "Your password must be at least 5 characters long"
                    },
         Confirm_Password: {
                    required: "Please provide a confirm password",
                    equalTo: "Please enter the same password as above"
                    }
        },
        submitHandler: function(form) { 
            // Your function call  
            return false; // return true will submit form
            }
    });
});
</script>

Answer 3

也许不是检查密码是否匹配，而是可以在验证中添加新规则？类似的东西：

           ... "Password": {
            required: true,
            minlength: 5
        },
        "Confirm-Password": {
            required: true,
            equalTo: "#Password"} ....

和消息添加：

... messages: {
           "Password": "Your message",

        }...

以及所有类似的东西：`

$(document).ready(function () {
$("Your form name").validate({
    rules: {
        "Username": {
            required: true,
        },
        "Password": {
            required: true,
            minlength: 5
        },
        "Confirm-Password": {
            required: true,
            equalTo: "#Password"
        },
        "email": {
            required: true,
            email: true
        }
    }
        messages: {
            "Password": "Your message",
            "email": "Your Message",
        },
        submitHandler: function (form) {
            form.submit();
        }
    });
});`

Answer 4

试试这个。我在提交按钮上添加onclick事件以调用函数validateForm()

HTML

<form id="register" name="register">
<label for ="Username"> Username </label><br>
<input type="text" class="register-control" id="Username" name="Username" placeholder="Enter Username"> <br><br>
<label for ="Password"> Password </label><br>
<input type="password" class="register-control" id="Password" name="Password" placeholder="Enter Password" ><br><br>
<label for ="Confirm-Password"> Confirm Password </label><br>
<input type="password" class="register-control" id="Confirm-Password" name="Confirm-Password" placeholder="Confirm Password" ><br><br>

<label for="email" > Email </label><br>
<input type ="email" class="register-control" id="email" name="email" placeholder="Enter Valid Email"><br><br>
<button type="submit" onclick="validateForm()">Submit</button>

</form>

这是validateForm()

<script type="text/javascript">
    function validateForm() {
        var username = $('#Username'),
            password = $('#Password'),
            confirm  = $('#Confirm-Password'),
            email    = $('#email');

        $('#register').submit(function(ev){
            // check if all fields is not empty
            if(username.val() === '' || password.val() === '' || confirm.val() === '' || email.val() === '') {
                ev.preventDefault(); // prevent form submit
                alert('All fields are required.'); //alert message
                //check if password and confirm password is equal
            } else if(password.val() != confirm.val()){
                ev.preventDefault(); // prevent form submit
                alert('password did not match.'); //alert message
            } else {
                return true; // submit form if validation has passed.
            }
        });
    }
</script>

Answer 5

可能你错过了 - 你需要在

中使用method =“post”

http://jsfiddle.net/dLbLS/

    <form id="register" name="register"  method="post" onsubmit="validateForm();" >
    <label for ="Username"> Username </label><br>
  <input type="text" class="register-control" id="Username" name="Username" placeholder="Enter Username"> <br><br>
  <label for ="Password"> Password </label><br>
 <input type="password" class="register-control" id="Password" name="Password"  placeholder="Enter Password" ><br><br>
  <label for ="Confirm-Password"> Confirm Password </label><br>
  <input type="password" class="register-control" id="Confirm-Password" name="Confirm-Password" placeholder="Confirm Password" ><br><br>

  <label for="email" > Email </label><br>
  <input type ="email" class="register-control" id="email" name="email" placeholder="Enter Valid Email"><br><br>
 <button type="submit" >Submit</button>

 </form>

Answer 6

使用此代码

    <input type="button" id="close" value="Submit" onClick="window.location = 'validateForm()'">

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在提交表单上调用javascript函数

6 个答案: