Question

我要玩SWF，当我使用PHP（src="uploads/<?php echo $tab['banner'] ?>"）时，它无法正常工作。你能告诉我如何在这里使用php吗？当我写src="uploads/223.swf"时它可以正常工作。

我的代码是：

<object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=7,0,19,0" height="350" width="235">
<param name="movie" value="uploads/<?php echo $tab['banner']  ?>">
<param name="quality" value="high">
<param value="transparent" name="wmode">
<embed wmode="transparent" allowscriptaccess="sameDomain" src="uploads/<?php echo    $tab['banner']  ?>" quality="high" pluginspage="http://www.macromedia.com/go/getflashplayer" type="application/x-shockwave-flash" height="350" width="235">
</object>

Answer 1

您可以简单地替换

value="uploads/<?php echo $tab['banner'] ?>"到

value="<?php echo 'uploads/'.$tab['banner'] ?>"

您可以尝试使用此代码

<object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=7,0,19,0" height="350" width="235">
<param name="movie" value="<?php echo 'uploads/'.$tab['banner']  ?>">
<param name="quality" value="high">
<param value="transparent" name="wmode">
<embed wmode="transparent" allowscriptaccess="sameDomain" src="<?php echo 'uploads/'.$tab['banner']  ?>" quality="high" pluginspage="http://www.macromedia.com/go/getflashplayer" type="application/x-shockwave-flash" height="350" width="235">
    </object>

如何在播放SWF时定义PHP变量

1 个答案: