Question

我在Google Play服务中阅读了有关leaderboards的所有文档，似乎当我调用GameClient的submitScore函数时，该服务仅考虑提交的最高分数。 E.g：

第一个电话：

gamesclient.submitScore( 100 );

现在球员得分为100

第二次电话：

gamesclient.submitScore( 150 );

现在球员得分为150

第3次电话：

gamesclient.submitScore( 100 );

玩家得分仍然是150.提交的值不会超过最后一个，因此会被忽略。

是否有一种简单的方法可以检索最后一个玩家得分，总结新得分并提交总数以创建增量得分排行榜？像

这样的东西

int old_score = ...GET LAST PLAYER SCORE...
int new_score = old_score + current_game_score;
gamesclient.submitScore( new_score );

Answer 1

到目前为止没有测试过，但我认为这是要走的路：

    PendingResult<Leaderboards.LoadPlayerScoreResult> result = Games.Leaderboards.loadCurrentPlayerLeaderboardScore(gameHelper.getApiClient(),"LEADERBOARD_ID",LeaderboardVariant.TIME_SPAN_ALL_TIME, LeaderboardVariant.COLLECTION_PUBLIC);
    result.setResultCallback(new ResultCallback<Leaderboards.LoadPlayerScoreResult>() {
        @Override
        public void onResult(Leaderboards.LoadPlayerScoreResult loadPlayerScoreResult) {
            Games.Leaderboards.submitScore(gameHelper.getApiClient(), "LEADERBOARD_ID",loadPlayerScoreResult.getScore().getRawScore()+ score);
        }

Answer 2

不幸的是，似乎没有一种内置的方法可以做到这一点。但是，您可以使用Cloud Save来保存播放器的最新分数，然后使用它。

或者，（这可能看起来有点俗气）每次提交分数时，将该分数保存在SharedPreferences中，然后当您提交另一分数时，使用该首选项增加分数而不是设置全新之一。

希望这有帮助，如果你真的不想解决问题，请告诉我，我会尝试找到另一种解决方案......

Answer 3

这就是我想出来的......

@Override
    public void postNewScore(final int finalScore, final ArrayList<String> theseBoards) {
        //posts score update to any theseBoards... most likely 2 boards
        for (final String anID : theseBoards) {
            aHelper.getGamesClient().loadPlayerCenteredScores(new OnLeaderboardScoresLoadedListener() {

            @Override
            public void onLeaderboardScoresLoaded(int statusCode, Leaderboard leaderboard, LeaderboardScoreBuffer scores) {
                if(statusCode == GamesClient.STATUS_OK){
                    if(scores.getCount() == 0){
                        aHelper.getGamesClient().submitScore(anID, finalScore);
                        dLog("submitted a score because there were no scores period");
                    } else {
                        for (LeaderboardScore s : scores) {
                            if(s.getScoreHolder().getPlayerId().contains(aHelper.getGamesClient().getCurrentPlayer().getPlayerId()) ||
                                    aHelper.getGamesClient().getCurrentPlayer().getPlayerId().contains(s.getScoreHolder().getPlayerId())){
                                aHelper.getGamesClient().submitScore(anID, finalScore + s.getRawScore());
                                dLog("just submitted " + (finalScore + s.getRawScore()));
                                scores.close();
                                return;
                            }
                        }
                        //if to here, then no score on the current page, which means the player does not have a score
                        aHelper.getGamesClient().submitScore(anID, finalScore);
                        dLog("because no entry, just submitted " + (finalScore));
                    }
                } 
                scores.close();
            }
        }, anID, LeaderboardVariant.TIME_SPAN_ALL_TIME, LeaderboardVariant.COLLECTION_SOCIAL, 1);
        }

    }

Answer 4

虽然您已经获得了如何增加分数的示例，但您无法将排行榜用作排名降低的排名表。

谷歌目前只允许该设施隐藏数十名疑似骗子。如果有某种方法可以降低分数或完全删除分数，那么你就可以按照自己的意愿去做。

我认为这背后的原因是，如果他们让你修改已经发布的分数，那么会削弱用户对Google Play游戏服务平台以及游戏中信任的信任 - 以扭曲玩家喜欢拥有的内容（原谅行话）。

随着时间的推移，这导致得分通胀，我认为他们在内部使用64位整数：

  /**
   * Submit a score to the leaderboard for the currently signed-in player.
   * The score is ignored if it is worse (as defined by the leaderboard
   * configuration) than a previously submitted score for the same player.
   */
  void SubmitScore(std::string const &leaderboard_id, uint64_t score);

你可以但是将排行榜的固定位置小数点位置修改为此通胀的课程调整。我不会。

很抱歉，如果这不是主题，请让Google在未来的更新中考虑这一点。

Answer 5

如果有人仍在寻找解决方案，根据最新的android版本，可以按以下步骤进行操作：

private LeaderboardsClient mLeaderboardsClient = Games.getLeaderboardsClient(this, googleSignInAccount);    

private void updateLeaderboards(final String leaderboardId) {
        mLeaderboardsClient.loadCurrentPlayerLeaderboardScore(
                leaderboardId,
                LeaderboardVariant.TIME_SPAN_ALL_TIME,
                LeaderboardVariant.COLLECTION_PUBLIC
        ).addOnSuccessListener(new OnSuccessListener<AnnotatedData<LeaderboardScore>>() {
            @Override
            public void onSuccess(AnnotatedData<LeaderboardScore> leaderboardScoreAnnotatedData) {
                if (leaderboardScoreAnnotatedData.get() == null)
                    mLeaderboardsClient.submitScore(leaderboardId, 1);
                else {
                    long currentscore = leaderboardScoreAnnotatedData.get().getRawScore();
                    mLeaderboardsClient.submitScore(leaderboardId, currentscore + 1);
                }
            }
        });
    }

如何在Android Google Play服务的排行榜中增加玩家得分？

5 个答案: