Question

我有2个关联。具有相同结构但只有一个ID的数组是相同的。每当特定ID相同时，我需要从IncludeArray向MainArray添加内容。

以下是数组的示例（MainArray最多可容纳100个或更多项，该示例仅包含部分实际内容）：

$MainArray = Array
 (
   [0] => Array
      (
        [item_id] => 1
        [name] => Test1
        [helptxt] => Helptext for item-id 1.
        [type_id] => 1      #could be the same for many other items!!
      )
   [1] => Array
      (
        [item_id] => 2
        [name] => Test2
        [helptxt] => Helptext for item-id 2.
        [type_id] => 2      #could be the same for many other items!!
      )
   and a lot more Arrays
 )


$IncludeArray = Array
(
  [0] => Array
      (
        [type_id] => 1
        [typetitle] => Number
        [typedesc] => Description Text type_id 1
      )
  [1] => Array
      (
        [type_id] => 2
        [typetitle] => Value
        [typedesc] => Description Text type_id 2
      )
 )

所需的新数组应为：

 $NewMainArray = Array
 (
   [0] => Array
      (
        [item_id] => 1
        [name] => Test
        [helptxt] => Helptext for item-id 1.
        [type_id] => 1
        [typetitle] => Number
        [typedesc] => Description Text type_id 1
      )
   [1] => Array
      (
        [item_id] => 2
        [name] => Test2
        [helptxt] => Helptext for item-id 2.
        [type_id] => 2
        [typetitle] => Value
        [typedesc] => Description Text type_id 2
      )
    And so on with all other items in the Array.
 )

因此，每次在$ MainArray中找到type_id时，[typetitle] + [typedesc]的内容应该添加到$ NewMainArray。

我的大多数测试都以仅合并Arrays或仅添加$ IncludeArray一次结束。甚至我的论坛搜索都没有让我找到解决方案。

数组是从2个单独的DB-Requests创建的，我无法加入（已尝试多次尝试）。这与不同的WHERE和AND子句有关，这些子句不适用于已连接的请求。

我希望有一种聪明的方法来获得所需的$ NewMainArray。顺便说一句，我使用PHP4，我是PHP的新手（至少对于这种问题）。

非常感谢你的帮助。

Answer 1

试试这个：


/**
 * Simulates relational table behaviour by joining data matching an ID value.
 * Works with single-nested arrays.
 *
 * @author Joel A. Villarreal Bertoldi
 *
 * @param  $source           array     The source array.
 * @param  $include_to_row   array     The row where we'll deposit the joined data.
 * @param  $match            string    Unique id field name.
 * 
 * @return array             Row with joined data.
 */

function includeFromArray($source, $include_to_row, $match)
{
  foreach ($source as $source_row)
  {
    if ($source_row[$match] == $include_to_row[$match])
    {
      foreach ($source_row as $source_column_key => $source_column_value)
      {
        $include_to_row[$source_column_key] = $source_column_value;
      }
    }
  }
  return $include_to_row;
}

for ($ma = 0; $ma < count($MainArray); $ma++)
  $NewMainArray[$ma] = includeFromArray($IncludeArray, $MainArray[$ma], "type_id");

结果：


Array
(
    [0] => Array
        (
            [item_id] => 1
            [name] => Test1
            [helptxt] => Helptext for item-id 1.
            [type_id] => 1
            [typetitle] => Number
            [typedesc] => Description Text type_id 1
        )

[1] => Array
    (
        [item_id] => 2
        [name] => Test2
        [helptxt] => Helptext for item-id 2.
        [type_id] => 2
        [typetitle] => Value
        [typedesc] => Description Text type_id 2
    )


)

Answer 2

看一下array_merge_recursive函数;）

http://nl2.php.net/manual/en/function.array-merge-recursive.php

PHP搜索数组并在id等于的位置添加内容

2 个答案: