Android:使用LAN下载播放mp4视频文件是可能的吗?

时间:2014-01-20 06:30:22

标签: android video stream download mp4

我是Android开发中的新手,遇到这个问题我的客户希望只使用LAN连接将视频文件从他的相机存储流传输到他的Android手机..这可能吗?我现在唯一可以做的就是从手机存储中播放视频并流式传输http或RTSP流视频,但是可以在通过LAN发送视频文件时流式传输视频文件吗?谢谢。

@ Androider-我为没有评论而道歉,因为我无论如何这是我现在的代码,任何形式的帮助将不胜感激,谢谢。 编辑:

客户端

` 公共类客户端扩展了Activi ty {

private Socket client;
 private FileInputStream fileInputStream;
 private BufferedInputStream bufferedInputStream;
 private OutputStream outputStream;
 private Button button;
 private TextView text;

 @Override
 public void onCreate(Bundle savedInstanceState) {
  super.onCreate(savedInstanceState);
  setContentView(R.layout.main);

  button = (Button) findViewById(R.id.button1);   
  text = (TextView) findViewById(R.id.textView1);   

  //Button press event listener
  button.setOnClickListener(new View.OnClickListener() {

   public void onClick(View v) {




File file = new File("/storage/emulated/BaseAhri.jpg"); 

try {

 client = new Socket("10.0.2.2", 4444);

 byte[] mybytearray = new byte[(int) file.length()]; 

 fileInputStream = new FileInputStream(file);
 bufferedInputStream = new BufferedInputStream(fileInputStream); 

 bufferedInputStream.read(mybytearray, 0, mybytearray.length); 

 outputStream = client.getOutputStream();

 outputStream.write(mybytearray, 0, mybytearray.length);
 outputStream.flush();
 bufferedInputStream.close();
 outputStream.close();
       client.close();

       text.setText("File Sent");


} catch (UnknownHostException e) {
 e.printStackTrace();
} catch (IOException e) {
 e.printStackTrace();
}

服务器端

private static ServerSocket serverSocket;
private static Socket clientSocket;
private static InputStream inputStream;
private static FileOutputStream fileOutputStream;
private static BufferedOutputStream bufferedOutputStream;
private static int filesize = 10000000; 
private static int bytesRead;
private static int current = 0;

public static void main(String[] args) throws IOException {


    serverSocket = new ServerSocket(4444); 

    System.out.println("Server started. Listening to the port 4444");


    clientSocket = serverSocket.accept();


    byte[] mybytearray = new byte[filesize];  

    inputStream = clientSocket.getInputStream();
    fileOutputStream = new FileOutputStream("/sdcard/DCIM/Camera/BaseAhri.jpg");
    bufferedOutputStream = new BufferedOutputStream(fileOutputStream);});
   System.out.println("Receiving...");


    bytesRead = inputStream.read(mybytearray, 0, mybytearray.length);
    current = bytesRead;

    do {
        bytesRead = inputStream.read(mybytearray, current, (mybytearray.length - current));
        if (bytesRead >= 0) {
            current += bytesRead;
        }
    } while (bytesRead > -1);


    bufferedOutputStream.write(mybytearray, 0, current);
    bufferedOutputStream.flush();
    bufferedOutputStream.close();
    inputStream.close();
    clientSocket.close();
    serverSocket.close();

    System.out.println("Sever recieved the file");

}
  

错误服务器端

     

[2014-01-22 15:20:15 - AndroidSocketSERVER] ActivityManager:起始:意图{act = android.intent.action.MAIN cat = [android.intent.category.LAUNCHER] cmp = com.javacodegeeks.android .androidsocketserver / .Server}

     

[2014-01-22 15:20:15 - AndroidSocketSERVER] ActivityManager:错误类型3

     

[2014-01-22 15:20:15 - AndroidSocketSERVER] ActivityManager:错误:活动类{com.javacodegeeks.android.androidsocketserver / com.javacodegeeks.android.androidsocketserver.Server}不存在。

在客户端,它在我发送后崩溃。不确定这是否是一个错误,因为我的服务器有问题....

@Androider -Sorry for late update,这是我的结果代码,我现在能够传递视频文件并按位控制它但问题是我的数据总是因为缺少字节或类似的东西而被破坏现在我怎么流呢?我无法播放该文件,因为它不完整?如果是这样的话那么字节控制的目的是什么?我希望你能再次帮助我。

COde客户端和服务器:

serverTransmitButton = (Button) findViewById(R.id.button_TCP_server);
    serverTransmitButton.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
            Log.i("Start Server Button Clicked", "yipee");

            try {
                // create socket
                // TODO: the port should match the one in Client
                ServerSocket servsock = new ServerSocket(5005);
                while (true) {
                    Log.i("************", "Waiting...");

                    Socket sock = servsock.accept(); // blocks until connection opened
                    Log.i("************", "Accepted connection : " + sock);

                    // sendfile

                    // TODO: put the source of the file

                        int filesize=8192;
                    File myFile = new File ("/sdcard/DCIM/Camera/test.mp4");
                    byte [] mybytearray  = new byte [filesize];

                    Log.i("####### file length = ", String.valueOf(myFile.length()) );
                    FileInputStream fis = new FileInputStream(myFile);
                    BufferedInputStream bis = new BufferedInputStream(fis);
                    bis.read(mybytearray,0,mybytearray.length);
                    OutputStream os = sock.getOutputStream();
                    Log.i("************", "Sending...");
                    int read;
                    while((read = fis.read(mybytearray)) != -1){
                    os.write(mybytearray,0,read);


                    }

                    os.flush();
                    os.close();
                    fis.close();
                    bis.close();
                }   
            } catch (IOException e) {
                Log.i("Io execption ", "e: " + e);
            }

            Log.i("=============== the end of start ==============", "==");
        }   
    });

    clientReceiveButton = (Button) findViewById(R.id.button_TCP_client);
    clientReceiveButton.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
            Log.i("Read Button Clicked", "yipee");

            try {
                int bufferSize;// filesize temporary hardcoded

                long start = System.currentTimeMillis();
                int bytesRead;
                int current;
                // localhost for testing
                // TODO: server's IP address. Socket should match one above in server
                Socket sock = new Socket("192.168.123.186",5005);

                Log.i("************", "Connecting...");

                // receive file
                bufferSize=sock.getReceiveBufferSize();
                byte [] mybytearray  = new byte [bufferSize];
                InputStream is = sock.getInputStream();

                FileOutputStream fos = new FileOutputStream("/storage/emulated/0/testinggo.mp4");
                BufferedOutputStream bos = new BufferedOutputStream(fos);
                bytesRead = is.read(mybytearray,0,mybytearray.length);


                while((current = is.read(mybytearray)) >0){
                bos.write(mybytearray, 0 , current);
                }

                bos.flush();
                bos.close();
                is.close();
                                    sock.close




            } catch ( UnknownHostException e ) {
                Log.i("******* :( ", "UnknownHostException");
            } catch (IOException e){
                Log.i("Read has IOException", "e: " + e);
            }

            Log.i("=============== the end of read ===============", "==");

        }
    });


}

}

1 个答案:

答案 0 :(得分:0)

实际上是。您需要在应用程序中构建自己的套接字服务器并从中播放视频。然后,您将控制字节输入流并将下载的部分保存到文件,而相同的部分将转到mediaplayer