带有线程执行的Java套接字

时间:2010-01-23 08:07:17

标签: java sockets multithreading

我编写了一个套接字侦听器,它应该侦听端口80和81,当数据到达这些端口时,会对这些数据执行操作。我希望这个监听器同时监听这两个端口并以下列方式编码。

 import java.net.*;
    import java.io.*;
    import java.text.DateFormat;
    import java.text.SimpleDateFormat;

    public class MultipleSocketServer implements Runnable {

     private int a;
  private ServerSocket connection;
  private String TimeStamp;
  private int ID;
public static void main(String[] args){

       // System.out.print("ip");
     // String gh="12345";
      //System.out.println(gh.substring(1,3));
  int port = 80;
  int port1 = 81;
  int count = 0;
  double a=234.52121;

   //System.out.println(bf3.toString());
    try{

      ServerSocket socket1 = new ServerSocket(port);
      ServerSocket socket2=new ServerSocket(port1);
      System.out.println("MultipleSocketServer Initialized");
      Runnable runnable = new MultipleSocketServer(socket1, ++count);
        Runnable run = new MultipleSocketServer(socket2, ++count);
        Thread thread = new Thread(runnable);
        Thread thread1 = new Thread(run);
      while (true) {
        //Socket connection = socket1.accept();

        thread.start();
        thread1.start();
      }
    }

    catch (Exception e) {}
  }
MultipleSocketServer(ServerSocket s, int i) {
  this.connection = s;
  this.ID = i;
}
public void run() {
    while(true){


    try {
        Socket incoming=connection.accept();


            BufferedInputStream is = new BufferedInputStream(incoming.getInputStream());
            int character;
     while((character = is.read())!=-1) {
    .
    .
    do the input data handling here
    .
    .

    }
    }
    catch(Exception e){}
    }
    }
}

但由于某些原因,这似乎并未显示线程/并发行为。 我正在使用Hyperterminal测试此代码,每次断开与超级终端的连接时,程序执行停止并且“Socket is closed”异常被引发。

任何指针都会有很大的帮助

干杯

1 个答案:

答案 0 :(得分:1)

你在无限循环中启动线程。

while (true) {
  //Socket connection = socket1.accept();
  thread.start();
  thread1.start();
}

我认为,这是在

中处理(忽略)的
} catch (Exception e) {}

但是,我怀疑您描述的问题出在您未包含的处理代码中。一个非常明显的想法:你不打电话给connection.close()而不是incoming.close(),对吗?