Question

在我的项目中，我需要创建一个导航应用程序来向盲人用户发送指示，因此我需要获取该Google地图中所有路径节点的音轨。我在网上引用了许多导航教程，但我没有得到我需要的东西。如有任何帮助，我很感谢你。

这是我的jsonparser类

public class DirectionsJSONParser {

/** Receives a JSONObject and returns a list of lists containing latitude and longitude */
public List<List<HashMap<String,String>>> parse(JSONObject jObject){

    List<List<HashMap<String, String>>> routes = new ArrayList<List<HashMap<String,String>>>() ;
    JSONArray jRoutes = null;
    JSONArray jLegs = null;
    JSONArray jSteps = null;

    try {
        jRoutes = jObject.getJSONArray("routes");

        /** Traversing all routes */
        for(int i=0;i<jRoutes.length();i++){
            jLegs = ( (JSONObject)jRoutes.get(i)).getJSONArray("legs");
            List path = new ArrayList<HashMap<String, String>>();

            /** Traversing all legs */
            for(int j=0;j<jLegs.length();j++){
                jSteps = ( (JSONObject)jLegs.get(j)).getJSONArray("steps");

                /** Traversing all steps */
                for(int k=0;k<jSteps.length();k++){
                    String polyline = "";
                   // polyline = (String)((JSONObject)((JSONObject)jSteps.get(k)).get("polyline")).get("formatted_address");
                    polyline = (String)((JSONObject)((JSONObject)jSteps.get(k)).get("polyline")).get("points");
                    List<LatLng> list = decodePoly(polyline);

                    /** Traversing all points */
                    for(int l=0;l<list.size();l++){
                        HashMap<String, String> hm = new HashMap<String, String>();
                        hm.put("lat", Double.toString(((LatLng)list.get(l)).latitude) );
                        hm.put("lng", Double.toString(((LatLng)list.get(l)).longitude) );
                        path.add(hm);
                    }
                }
            routes.add(path);
        }
    }

} catch (JSONException e) {
    e.printStackTrace();
}catch (Exception e){
}

return routes;
}
/**
* Method to decode polyline points
* Courtesy : http://jeffreysambells.com/2010/05/27/decoding-polylines-from-google-maps-direction-api-with-java
* */
private List<LatLng> decodePoly(String encoded) {

    List<LatLng> poly = new ArrayList<LatLng>();
    int index = 0, len = encoded.length();
    int lat = 0, lng = 0;

    while (index < len) {
        int b, shift = 0, result = 0;
        do {
            b = encoded.charAt(index++) - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlat = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lat += dlat;

        shift = 0;
        result = 0;
        do {
            b = encoded.charAt(index++) - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlng = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lng += dlng;

        LatLng p = new LatLng((((double) lat / 1E5)),
            (((double) lng / 1E5)));
        poly.add(p);
    }

    return poly;
}

}

Answer 1

没有方向的音频曲目，但看起来你正在使用Google Directions API，如果你查看documentation，你会看到路径的说明在JSON中返回给你为html_instructions。

那么你要做的就是使用说明并使用Text To Speech (TTS)引擎说出来。

<强>无论其

使用Directions API作为转弯导航forbidden，如TOS

中所述

Google Maps/Google Earth APIs Terms of Service

Last updated: May 27, 2009
...
10. License Restrictions. Except as expressly permitted under the Terms, or unless you
have received prior written authorization from Google (or, as applicable, from the
provider of particular Content), Google's licenses above are subject to your adherence
to all of the restrictions below. Except as explicitly permitted in Section 7 or the
Maps APIs Documentation, you must not (nor may you permit anyone else to):
...
10.9 use the Service or Content with any products, systems, or applications for or in
connection with:

(a) real time navigation or route guidance, including but not limited to turn-by-turn
route guidance that is synchronized to the position of a user's sensor-enabled device;

and may be disabled for certain apps (somehow, at least on Android)... FromGeocode
scraping in .NET conversation:
This is not allowed by the API terms of use. You should not scrape Google Maps to
generate geocodes. We will block services that do automated queries of our servers.

Bret Taylor
Product Manager, Google Maps

我们如何获得谷歌地图v2中所有路线节点的音轨

1 个答案: