Question

以下是在Django中定义MinLengthValidator的方法：

class MinLengthValidator(BaseValidator):
    compare = lambda self, a, b: a < b
    clean = lambda self, x: len(x)
    message = ungettext_lazy(
        'Ensure this value has at least %(limit_value)d character (it has %(show_value)d).',
        'Ensure this value has at least %(limit_value)d characters (it has %(show_value)d).',
        'limit_value')
    code = 'min_length'

我尝试在我的代码中更改错误消息，如下所示：

password_min_length_validator = MinLengthValidator(8)
password_min_length_validator.message = ungettext_lazy(
    'Ensure password has at least %(limit_value)d character (it has %(show_value)d).',
    'Ensure password has at least %(limit_value)d characters (it has %(show_value)d).',
    'limit_value')

但是我收到了这个错误：

ugettext() takes exactly 1 argument (3 given)

我这样做就像django.core.validators一样。

Answer 1

看起来您正在使用早期版本的Django，因此您应该将代码基于Django版本的MinLengthValidator，而不是当前的实现。您收到错误是因为Django 1.6中更改了ungettext_lazy方法（请参阅ticket #19160）。

例如，在Django 1.5.X中，您可以这样做：

from django.utils.translation import ugettext_lazy as _

class MinLengthValidator(BaseValidator):
    compare = lambda self, a, b: a < b
    clean = lambda self, x: len(x)
    message = _('Ensure this value has at least %(limit_value)d characters (it has %(show_value)d).')
    code = 'min_length'

password_min_length_validator = MinLengthValidator(8)
password_min_length_validator.message = _(
    'Ensure password has at least %(limit_value)d characters (it has %(show_value)d).',
)

在实例化验证器后，您可以将其子类化为

，而不是设置messages属性

class MyMinLengthValidator(MinLengthValidator):
    message = _('Ensure my_field has at least %(limit_value)d characters (it has %(show_value)d).')

my_min_length_validator = MyMinLengthValidator(8)

或者，您可以在表单字段中使用error_messages选项：

class MyForm(forms.Form):
    my_field = forms.CharField(validators=[MinLengthValidator(8)], 
                        error_messages={'min_length': _('Ensure my_field has at least %(limit_value)d characters (it has %(show_value)d).')
})

Django：更改MinLengthValidator错误消息

1 个答案: