Question

我有我的实体：

@Entity
@Table(name="performances")
@AssociationOverrides({
    @AssociationOverride(name="id.player", joinColumns=@JoinColumn(name="player_id")),
    @AssociationOverride(name="id.season", joinColumns=@JoinColumn(name="season_id"))
})
public class Performance extends AbstractEntity<PerformanceID> {

    private static final long serialVersionUID = 1L;

    @EmbeddedId
    @Getter @Setter
    private PerformanceID id;
    @Getter @Setter
    private int goals;

    public Player getPlayer(){
        return id.getPlayer();
    }

    public Season getSeason(){
        return id.getSeason();
    }

和

@Embeddable
public class PerformanceID implements Serializable {

    private static final long serialVersionUID = 1L;

    @ManyToOne(fetch=FetchType.LAZY, targetEntity=Player.class)
    @JoinColumn(name="player_id")
    @Getter @Setter
    private Player player;
    @ManyToOne(fetch=FetchType.LAZY, targetEntity=Season.class)
    @JoinColumn(name="season_id")
    @Getter @Setter
    private Season season;

如何选择玩家名称为“Claudio”的演出记录？在HQL中它只是起作用：

Query query = getSession().createQuery("from Performance where id.player.name = 'Claudio'");
return query.list();

但我需要通过Criteria API来实现。以下代码将失败：

Criteria criteria = getSession().createCriteria(Performance.class);
criteria.add(Restrictions.ilike("id.player.name", "Claudio"));
return criteria.list();

org.hibernate.QueryException：无法解析属性： id.player.name： pl.andrzejcichon.criterionlazydatamodel.entities.Performance at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException（AbstractPropertyMapping.java:83）在 org.hibernate.persister.entity.AbstractPropertyMapping.toColumns（AbstractPropertyMapping.java:98）在 org.hibernate.persister.entity.BasicEntityPropertyMapping.toColumns（BasicEntityPropertyMapping.java:61）在 org.hibernate.persister.entity.AbstractEntityPersister.toColumns（AbstractEntityPersister.java:1912）在 org.hibernate.loader.criteria.CriteriaQueryTranslator.getColumns（CriteriaQueryTranslator.java:523）在 org.hibernate.loader.criteria.CriteriaQueryTranslator.findColumns（CriteriaQueryTranslator.java:538）在 org.hibernate.criterion.LikeExpression.toSqlString（LikeExpression.java:80）在 org.hibernate.loader.criteria.CriteriaQueryTranslator.getWhereCondition（CriteriaQueryTranslator.java:419）在 org.hibernate.loader.criteria.CriteriaJoinWalker。（CriteriaJoinWalker.java:123）在 org.hibernate.loader.criteria.CriteriaJoinWalker。（CriteriaJoinWalker.java:92）在 org.hibernate.loader.criteria.CriteriaLoader。（CriteriaLoader.java:93）在org.hibernate.internal.SessionImpl.list（SessionImpl.java:1599）at org.hibernate.internal.CriteriaImpl.list（CriteriaImpl.java:374）at at pl.andrzejcichon.criterionlazydatamodel.repository.impl.PerformanceDatabaseRepository.customList（PerformanceDatabaseRepository.java:29）在 pl.andrzejcichon.criterionlazydatamodel.repository.impl.PerformanceDatabaseRepositoryTest.test（PerformanceDatabaseRepositoryTest.java:24） at sun.reflect.NativeMethodAccessorImpl.invoke0（Native Method）at sun.reflect.NativeMethodAccessorImpl.invoke（未知来源）at sun.reflect.DelegatingMethodAccessorImpl.invoke（未知来源）at java.lang.reflect.Method.invoke（未知来源）at org.junit.runners.model.FrameworkMethod $ 1.runReflectiveCall（FrameworkMethod.java:45）在 org.junit.internal.runners.model.ReflectiveCallable.run（ReflectiveCallable.java:15）在 org.junit.runners.model.FrameworkMethod.invokeExplosively（FrameworkMethod.java:42）在 org.junit.internal.runners.statements.InvokeMethod.evaluate（InvokeMethod.java:20）在 org.springframework.test.context.junit4.statements.RunBeforeTestMethodCallbacks.evaluate（RunBeforeTestMethodCallbacks.java:74）在 org.springframework.test.context.junit4.statements.RunAfterTestMethodCallbacks.evaluate（RunAfterTestMethodCallbacks.java:83）在 org.springframework.test.context.junit4.statements.SpringRepeat.evaluate（SpringRepeat.java:72）在 org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild（SpringJUnit4ClassRunner.java:231）在 org.junit.runners.BlockJUnit4ClassRunner.runChild（BlockJUnit4ClassRunner.java:47）在org.junit.runners.ParentRunner $ 3.run（ParentRunner.java:231）at org.junit.runners.ParentRunner $ 1.schedule（ParentRunner.java:60）at org.junit.runners.ParentRunner.runChildren（ParentRunner.java:229）at at org.junit.runners.ParentRunner.access $ 000（ParentRunner.java:50）at org.junit.runners.ParentRunner $ 2.evaluate（ParentRunner.java:222）at at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate（RunBeforeTestClassCallbacks.java:61）在 org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate（RunAfterTestClassCallbacks.java:71）在org.junit.runners.ParentRunner.run（ParentRunner.java:300）at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run（SpringJUnit4ClassRunner.java:174）在 org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run（JUnit4TestReference.java:50）在 org.eclipse.jdt.internal.junit.runner.TestExecution.run（TestExecution.java:38）在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests（RemoteTestRunner.java:467）在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests（RemoteTestRunner.java:683）在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run（RemoteTestRunner.java:390）在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main（RemoteTestRunner.java:197）

另一个尝试：

Criteria criteria = createCriteria();
criteria.createAlias("id.player", "player");
criteria.add(Restrictions.ilike("player.name", "Claudio"));
return criteria.list();

将生成查询：

Hibernate：选择this_.player_id作为player2_1_0_，this_.season_id为 season3_1_0_，this_.goals as goals1_0_ from performance this_ where player1_.name ilike？

但它会因SQLGrammarException失败：“表player1的缺少FROM子句_”

Answer 1

您的映射不正确。 EmbeddableId类应包含@Id（因此Serializable）值，而不是映射或复杂类型。您应该将映射移动到实体类，然后仅将其ID包含在EmbbedableId类中。请参阅以下示例（来自JPA 2.2规范）

@Embeddable
public class DependentId {
    String name;
    long empPK;   // corresponds to PK type of Employee
}

@Entity
public class Dependent {
    @EmbeddedId DependentId id;

    // id attribute mapped by join column default
    @MapsId("empPK") // maps empPK attribute of embedded id
    @ManyToOne Employee emp;
}

EmbeddedId的Hibernate标准

1 个答案: