在下面的代码中,我想将表c_files cf与两个括号内的第二个查询的结果(别名x)结合起来。
SELECT f_cl_path f,cf.f_id, 'xx' as jo
FROM c_files cf
LEFT JOIN
(SELECT f_cl_path f, f_id, f_workgroup, 'yy' as jo FROM myOtherTable
WHERE f_workgroup ='1234' AND f_status<=2) x
ON x.f_id=cf.f_id
WHERE cf.f_workgroup='798190' and jo='xx';
我想只获得jo='xx'
的元素。但这不起作用。当我使用jo='yy'
尝试时,我会得到一个结果,但我需要jo='xx'
。
答案 0 :(得分:1)
看到您的评论后,也许这张图片可能会有所帮助。
如果我没错,你的情况会是这样的:
SELECT f_cl_path f,cf.f_id
FROM c_files cf
LEFT JOIN (SELECT f_cl_path f, f_id, f_workgroup FROM myOtherTable
WHERE f_workgroup ='1234' AND f_status<=2) as x
ON x.f_id=cf.f_id
WHERE cf.f_workgroup='798190' and x.f_id IS NULL