Question

我正在尝试用cakephp创建分页，但是它给了我找不到的错误地址。在此服务器上找不到请求的地址'/ mygroup / newsfeed / page：2'。

我在日志文件中收到以下错误

Error: [MissingActionException] Action GroupsController::page:2() 
could not be found.
Exception Attributes: array (
'controller' => 'GroupsController',
'action' => 'page:2',
)

请在下面找到我的代码：

查看：

<?php if($this->params['paging']['NewsFeed']['pageCount'] > 1): ?>
<?php $this->paginator->options(array('url' => array('controller' => 'groups', 
'action'  => 'newsfeed', 'sluggroup' => $groupdata['Group']['group_slug'])));?>
<div class="paginationbiz">
     <ul>
        <li class="prevnext disablelink"><?php echo $this->paginator->prev('« Prev',array()); ?></li>
        <li><?php echo $this->paginator->numbers(); ?></li>
        <li class="prevnext"><?php echo $this->paginator->next('Next »',array()); ?></li>
    </ul>
</div>
<?php endif; ?>

routes.php文件

 Router::connect('/:sluggroup/:action/*', array('controller' => 'groups', 
'action' =>   'newsfeed'),array('pass' => array('sluggroup')));

控制器：

 $this->paginate = array(
            'conditions' => array('NewsFeed.group_id'=>$groupdata['Group']['id'],'NewsFeed.status'=>'A'),
            'joins' => array(
                    array(
                            'alias' => 'newslikes',
                            'table' => 'news_feed_likes',
                            'type' => 'LEFT',
                            'conditions' => array('newslikes.news_feed_id = NewsFeed.id','newslikes.user_id'=>$this->Auth->user('id'),'newslikes.status'=>'1')
                    ),


            ),
            'fields' => array('IFNULL(newslikes.user_id,0) AS likestatus','NewsFeed.id','NewsFeed.group_id','NewsFeed.posted_message','NewsFeed.event_id','NewsFeed.event_desc','NewsFeed.event_slug','NewsFeed.event_title','NewsFeed.doc_id','NewsFeed.doc_title','NewsFeed.doc_file','NewsFeed.doc_path','NewsFeed.alert_id','NewsFeed.alert_title','NewsFeed.alert_desc','NewsFeed.created','NewsFeed.user_id','NewsFeed.status','NewsFeed.newslike'
                    ,'IFNULL(newslikes.status,0) AS status'),
            'order' => array(
                    'NewsFeed.updated' => 'desc'
            ),'limit' =>10, 'page'=>1,
    );

    $this->set('newsfeed', $this->paginate( $this->NewsFeed ) );

Answer 1

由于同样的问题，你有similar question（也没有回答）。

你的问题是路线

Router::connect('/:sluggroup/:action/*', array('controller' => 'groups', 
                'action' =>   'newsfeed'),array('pass' => array('sluggroup')));

那，我的朋友，正在杀了你。对于像 domain.url / your-controller / your-action 这样的每个网址，您都可以，因为该网址与您的路线不符。但是，对于 domain.url / your-controller / your-action / some-parameter 这样的网址，您会得到一个匹配。

domain.url/your-controller/your-action != /:sluggroup/:action/*   //ok case
domain.url/sluggroup/action/*          == /:sluggroup/:action/*   //ok case

//NOT THE MATCH THE MATCH YOU WANT
domain.url/your-controller/your-action/params == /:sluggroup/:action/*

我看到的唯一选择是更改该路线，否则这将继续发生在您身上，不需要的匹配。现在，有两个选择......好吧，可能更多。如果获取sluggroup参数的url对应一个控制器，让我们称之为“GroupsController”，你可以做类似的事情

Router::connect('/groups/:sluggroup/:action/*', array('controller' => 'groups', 
                'action' =>   'newsfeed'),array('pass' => array('sluggroup')));

这将匹配 domain.com/groups/slug/action/etc ，但等网址，它仍然会为您提供同一控制器的其他操作的问题（例如 domain.com/groups/edit/2 ）。您可以避免为每个操作添加更多网址，例如

Router::connect('/groups/edit/*', array('controller' => 'groups', 
                'action' =>   'edit')));
Router::connect('/groups/edit', array('controller' => 'groups', 
                'action' =>   'edit')));
Router::connect('/groups/:sluggroup/:action/*', array('controller' => 'groups', 
                'action' =>   'newsfeed'),array('pass' => array('sluggroup')));

另一个选项是使路线跳过具有正则表达式参数的规则

Router::connect('/:sluggroup/:action/*', array('controller' => 'groups', 
                'action' =>   'newsfeed'),
                 array('pass' => array('sluggroup'),
                 array('sluggroup' => '[^(groups)]')));

我对正则表达式并不擅长，但我的想法是你只将该路由应用于sluggroup与正则表达式匹配的网址，否则跳过它，它将到达正确的路由。

似乎没有什么可持续的，你是不是没有像 domain.com/groups/newwsfeed/slug/other-params 这样的网址并保持简单？

在cakephp分页中找不到请求的地址错误

1 个答案: