Question

我正在使用Spring Framework / Data / HATEOAS并尝试添加Dozer。

我的spring-config.xml中有以下bean：

<?xml version="1.0" encoding="UTF-8"?>
<beans  xmlns="http://www.springframework.org/schema/beans"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"   
        xmlns:data="http://www.springframework.org/schema/data/jpa"
        xmlns:mvc="http://www.springframework.org/schema/mvc"
        xmlns:context="http://www.springframework.org/schema/context"
        xsi:schemaLocation="
            http://www.springframework.org/schema/beans
            http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
            http://www.springframework.org/schema/mvc
            http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
            http://www.springframework.org/schema/data/jpa
            http://www.springframework.org/schema/data/jpa/spring-jpa.xsd
            http://www.springframework.org/schema/context
            http://www.springframework.org/schema/context/spring-context-2.5.xsd">

    <bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
        <property name="database" value="POSTGRESQL" />
        <property name="databasePlatform" value="org.hibernate.dialect.PostgreSQLDialect" />
    </bean>

    <bean id="jpaDialect" class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" />

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
        <property name="dataSource" ref="dataSource" />
        <property name="jpaDialect" ref="jpaDialect" />
    </bean>

    <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="org.postgresql.Driver" />
        <property name="url" value="jdbc:postgresql://localhost:5432/cp" />
        <property name="username" value="cp_user" />
        <property name="password" value="+JMJ+pw0m2d" />
    </bean>

    <context:component-scan base-package="com.mydomain.data.assembler" />
    <data:repositories base-package="com.mydomain.repository" />

    <mvc:annotation-driven />

    <bean id="dozerFactory" class="org.dozer.spring.DozerBeanMapperFactoryBean" scope="singleton">
        <property name="mappingFiles" value="classpath*:/*mapping.xml"/>
    </bean>

</beans>

以下汇编程序：

@Component
public class UserResourceAssembler {

    @Inject 
    private Mapper dozerBeanMapper;

    public UserResource toResource(User user) {
        UserResource resource = dozerBeanMapper.map(user, UserResource.class);
        resource.add(linkTo(methodOn(UserController.class).get(user.getId())).withSelfRel());
        return resource;
    }

    public User toEntity(UserResource resource) {
        User user = dozerBeanMapper.map(resource, User.class);
        return user;
    }
}

所以， - 我对豆子和注射都很新 - 但我猜工厂豆是假的？注入Mapper。但Mapper肯定是空的。我知道我做得不对，但我做错了什么？

Answer 1

Spring将bean注入Spring托管bean。您正在使用非托管静态上下文。将UserResourceAssembler更改为托管bean：

@Component
public class UserResourceAssembler {

    @Inject
    private Mapper dozerBeanMapper;

    public UserResource toResource(User user) {
    }

    public User toEntity(UserResource resource) {
    }

}

请参阅why can't we autowire static fields in spring。

Answer 2

我会更喜欢上面的内容。但后来我读到了：

Dozer Singleton Startup Bean injetced as Null

那很有用。这是我的实施。

我从spring-config和上下文扫描中删除了bean。

我添加了这个课程：

@Singleton
public class DozerInstantiator {
    public static DozerBeanMapper getInstance(){
        return MapperHolder.instance;
    }

    private static class MapperHolder{
        static final DozerBeanMapper instance = new DozerBeanMapper();
    }
}

并更新了我的汇编程序：

public class UserResourceAssembler {

    private DozerBeanMapper mapper;

    public UserResourceAssembler() {
        mapper = DozerInstantiator.getInstance();
    }

    public UserResource toResource(User user) {     
        UserResource resource = mapper.map(user, UserResource.class);
        resource.add(linkTo(methodOn(UserController.class).get(user.getId())).withSelfRel());
        return resource;
    }

    public User toEntity(UserResource resource) {
        User user = mapper.map(resource, User.class);
        return user;
    }
}

Spring注入的bean为null

2 个答案: