Question

我正在编写一个程序，它接受10个数字作为输入，并使用并行数组显示数字的模式，以及将数字数组作为参数并返回数组中最常出现的值的方法。问题：然而，当我运行我的程序时它绝对没有输出，而且，我不知道如何实现并行数组。有人知道吗？谢谢。

import java.util.Scanner;

公共类模式{

public static void main(String[] args) {
}

public int computeMode(int[] nums) {
    Scanner scanner = new Scanner(System.in);

    int maxValue = -1;
    int maxCount = 0;
    int x = 0;
    //count how many times nums[i] appears in array

    System.out.println("Enter 10 numbers: ");
    for (int i = 0; i < 10; i++) {

        try { //try catch exception to catch decimal inputs as well as more /less than 10 integers
            x = scanner.nextInt();
        } catch (Exception e) {
            System.out.println("Invalid input! Please reenter 10 integer values.");
            scanner = new Scanner(System.in);
            i = -1;

            continue;
        }
        for (i = 0; i < nums.length; i++) {
            int count = 0;
            for (int j = 0; j < nums.length; j++) {
                if (nums[j] == nums[i]) {
                    count++;
                }
            }

            if (count > maxCount) {
                maxValue = nums[i];
                maxCount = count;
                System.out.println("The mode is: " + maxValue);
            }

        }

    }
    return maxValue;
}

}

Answer 1

主要功能是空的，所以它什么都没有，并且该功能不需要任何参数，因为您使用扫描仪读取数字

我认为你需要这个：

import java.util.Scanner;

class Mode {
    public static void main(String[] args) {
        computeMode();
    }

    public static void computeMode(){
        int nums[]=new int[10];
        Scanner scanner = new Scanner(System.in);

        int maxValue = -1;
        int maxCount = 0;
        int x = 0;
        //count how many times nums[i] appears in array

        System.out.println("Enter 10 numbers: ");
        for (int i = 0; i < 10; i++) {

            try { //try catch exception to catch decimal inputs as well as more /less than 10 integers
                x = scanner.nextInt();
                nums[i]=x;
            } 
            catch (Exception e) {
                System.out.println("Invalid input! Please reenter 10 integer values.");
                i =i -1;
                scanner.nextLine();

                continue;
            }
        }
        for (int i = 0; i < nums.length; i++) {
            int count = 0;
            for (int j = 0; j < nums.length; j++) {
                if (nums[j] == nums[i]) {
                    count++;
                }
            }

            if (count > maxCount) {
                maxValue = nums[i];
                maxCount = count;

            }

        }
    System.out.println("The mode is: " + maxValue);
    }


}

Answer 2

代码写x，但从不读它;读nums，但从不写;并实现computeMode，但从不调用它。

查找数组的模式：无输出

2 个答案: