如何通过选择All选项显示jqgrid数据表的所有数据?

时间:2014-01-09 07:26:29

标签: java jquery jqgrid

我正在使用JQuery Datatable将数据显示到grid.when我试图通过选择所有选项来访问所有数据。我每次都会收到一个错误。

数据表代码

$(document).ready(function () {
            $("#generalreport").dataTable({

                "bServerSide": true,
                "sScrollY": "370px",
                "sAjaxSource": "ajaxSearchGeneralReport.action",
                "bProcessing": true,

              "sPaginationType": "full_numbers",
                "bJQueryUI": true,
                "bLengthChange": true,
                "iDisplayLength" : -1,
                "aLengthMenu": [[50,100,300,-1],[50,100,300,'All']],

                 "sDom": 'T<"clear"><"H"lfr>t<"F"ip>',
                "oTableTools": {
                  "sSwfPath": "media/swf/copy_csv_xls_pdf.swf"
                }     
            });
        });

错误

ava.lang.IllegalArgumentException: fromIndex(0) > toIndex(-1)
    at java.util.SubList.<init>(AbstractList.java:604)
    at java.util.AbstractList.subList(AbstractList.java:468)
    at x.y.z.action.GeneralReportAction.execute(GeneralReportAction.java:119)

0 个答案:

没有答案