Question

我想以“2天，3小时，5分钟和8秒”的形式打印两个日期之间的差异。

我正在使用此代码调用Joda-Time库，但我遇到了一些麻烦。

Calendar cal = Calendar.getInstance();
DateTime firstSeen = new DateTime(cal.getTime());

cal.add(Calendar.HOUR, 24*8);
cal.add(Calendar.MINUTE, 10);
cal.add(Calendar.SECOND, 45);

DateTime lastSeen = new DateTime(cal.getTime());
Period period = new Period(firstSeen, lastSeen);

PeriodFormatter daysHoursMinutesSeconds = new PeriodFormatterBuilder()
    .appendDays()
    .appendSuffix(" day", " days")
    .appendSeparator(", ")
    .appendMinutes()
    .appendSuffix(" minute", " minutes")
    .appendSeparator(" and ")
    .appendSeconds()
    .appendSuffix(" second", " seconds")
    .toFormatter();

String periodFormatted;
periodFormatted = daysHoursMinutesSeconds.print(period);
System.out.println(periodFormatted);

应该打印的是“8天10分45秒”。相反，我得到“1天，10分45秒”;这一天似乎已经过了一周。如何告诉格式化程序忽略溢出并总结溢出到第一个单元的内容？

Answer 1

这是正确的输出，因为期间为“1周1天45分钟”且周字段未打印：

package com.stackoverflow.so21002436;

import org.joda.time.DateTime;
import org.joda.time.Period;
import org.joda.time.format.PeriodFormatter;
import org.joda.time.format.PeriodFormatterBuilder;

public class App {
    public static void main(final String[] args)
    {
        final DateTime firstSeen = DateTime.now();
        final DateTime lastSeen = firstSeen.plusDays(8).plusMinutes(10).plusSeconds(45);

        final Period period = new Period(firstSeen, lastSeen);
        System.err.println(period); // P1W1DT10M45S, ie. 1 day, 10 minutes and 45 seconds

        final PeriodFormatter daysHoursMinutesSeconds = new PeriodFormatterBuilder().appendDays()
                .appendSuffix(" day", " days")
                .appendSeparator(", ")
                .appendMinutes()
                .appendSuffix(" minute", " minutes")
                .appendSeparator(" and ")
                .appendSeconds()
                .appendSuffix(" second", " seconds")
                .toFormatter();

        final String periodFormatted = daysHoursMinutesSeconds.print(period);
        System.out.println(periodFormatted);
    }
}

或使用特定的PeriodType：

package com.stackoverflow.so21002436;

import org.joda.time.DateTime;
import org.joda.time.Period;
import org.joda.time.PeriodType;
import org.joda.time.format.PeriodFormatter;
import org.joda.time.format.PeriodFormatterBuilder;

public class App {
    public static void main(final String[] args)
    {
        final DateTime firstSeen = DateTime.now();
        final DateTime lastSeen = firstSeen.plusDays(8).plusMinutes(10).plusSeconds(45);

        final Period period = new Period(firstSeen, lastSeen, PeriodType.dayTime());
        System.err.println(period); // P8DT10M45S, ie. 8 days, 10 minutes and 45 seconds

        final PeriodFormatter daysHoursMinutesSeconds = new PeriodFormatterBuilder().appendDays()
                .appendSuffix(" day", " days")
                .appendSeparator(", ")
                .appendMinutes()
                .appendSuffix(" minute", " minutes")
                .appendSeparator(" and ")
                .appendSeconds()
                .appendSuffix(" second", " seconds")
                .toFormatter();

        final String periodFormatted = daysHoursMinutesSeconds.print(period);
        System.out.println(periodFormatted);
    }
}

请参阅Period(ReadableInstant, ReadableDuration, PeriodType)

Joda时间段打印

1 个答案: