我想动态重命名文件然后上传它。我从DB获取文件名。但是当我重命名文件时,它没有从DB获取名称值。它正在考虑我要添加的静态部分。这是我的代码
uploadId.php:
$con=mysqli_connect("localhost","root","****","database");
$result= mysqli_query($con,"SELECT op_id FROM Optrs_info WHERE op_id='1234'");
$res= mysqli_fetch_array($result);
$opid= $res["op_id"];
$id= $opid . "add2";
$_SESSION['id']= $id;
在这里,我正在使用新名称上传文件
<?php
include("uploadId.php");
$temp = explode(".", $_FILES["uploaded_file"]["name"]);
$extension = end($temp);
$path="/var/www/tcpdf/pictures/";
$filename=basename($_FILES["uploaded_file"]["name"]);
$filename = $_SESSION['id'] . (string) strrchr($filename, '.');
$filename = $_SESSION['id'] . '.' . $extension;
if(move_uploaded_file($_FILES["uploaded_file"]["tmp_name"],$path . $filename))
{
echo "Uploaded";
}
?>
当我尝试使用add2.jpeg上传新文件时,但未添加$ opid值。
答案 0 :(得分:3)
试试这个:
<?php
include("uploadId.php");
$temp = explode(".", $_FILES["uploaded_file"]["name"]);
$extension = end($temp);
$path="/var/www/tcpdf/pictures/";
$filename = basename($_FILES["uploaded_file"]["name"]);
$filename = $_SESSION['id'] . strrchr($filename, '.') . $extension;
if(move_uploaded_file($_FILES["uploaded_file"]["tmp_name"],$path . $filename))
{
echo "Uploaded";
}
?>