Question

以下一对多

CREATE TABLE source(id int, name varchar(10), PRIMARY KEY(id));
CREATE TABLE params(id int, source int, value int);

其中params.source是source.id的外键

INSERT INTO source values(1, 'yes');
INSERT INTO source values(2, 'no');

INSERT INTO params VALUES(1,1,1);
INSERT INTO params VALUES(2,1,2);
INSERT INTO params VALUES(3,1,3);

INSERT INTO params VALUES(4,2,1);
INSERT INTO params VALUES(5,2,3);
INSERT INTO params VALUES(6,2,4);

如果我有一个参数值列表（比如[1,2,3]），我如何在SQL中找到列表中所有值（源1，“是”）的所有源？ / p>

由于

Answer 1

SELECT s.*
FROM source AS s
 JOIN params AS p ON (p.source = s.id)
WHERE p.value IN (1,2,3)
GROUP BY s.id
HAVING COUNT(DISTINCT p.value) = 3;

您需要DISTINCT，因为不会阻止您的params.value重复。

Answer 2

编辑已修改以处理给定来源可能存在多个值的情况。

试试这个：

SELECT
    *
FROM
    source
WHERE
    (
        SELECT COUNT(DISTINCT value)
        FROM params
        WHERE params.source = source.id
          AND params.value IN (1, 2, 3)
    ) = 3

您也可以将其重写为GROUP BY：

SELECT
    source.*
FROM
    source
    INNER JOIN params ON params.source = source.id
WHERE
    params.value IN (1, 2, 3)
GROUP BY
    source.id,
    source.name
HAVING
    COUNT(DISTINCT params.value) = 3

在多方面，SQL一对多匹配ALL的一方

2 个答案: