Question

我目前正在为客户端将一个mysql项目翻译成sqlsrv而我遇到了一个问题。 Php抱怨$ query_pass是意外的，而实际上它正在被声明。当我使用mysql时，它工作，但我无法看到问题甚至可能与此远程相关。这是代码：

    <?php

session_start();
ob_start();

?>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<form action="<?php $current_file ?>" method="post">
        E-post: <input type="text" name="username"/><br>
        Lösenord: <input type="password" name="pass" /><br>
        <input type="submit" value="Logga in"/>
        </form><form action="http://localhost/update.php">
    <input type="submit" value="Skapa lösenord">
</form>

<?php

if(isset($_POST['username'])&&isset($_POST['pass']))
{
    $username = $_POST['username'];
    $password = $_POST['pass'];

    if(!empty($username)&&!empty($password))
    {

        $query = "SELECT login_id, password FROM users WHERE email = '$username'";
        $row = sqlsrv_fetch_array( $query, SQLSRV_FETCH_ASSOC)
        $query_pass = $row['password'];
        $_SESSION['id'] = $row['login_id']

        if($row && ($query_pass == NULL))
        {
            $next = "http://localhost/update.php";
                header('Location: '.$next);


        }
        else
        {
            if((sqlsrv_num_rows($query_run) == 0) || $query_pass != $password)
            {
                echo 'Ingen matchning av lösenord och användare hittad.';
            }else{
                $next = "http://localhost/title_choice.php";
                header('Location: '.$next);
            }
        }

    }else{
        echo "Användarnamn och lösenord behövs.";
    }

}

ob_end_flush();
?>

Answer 1

您在以下行找不到;：

$row = sqlsrv_fetch_array( $query, SQLSRV_FETCH_ASSOC)

Answer 2

另外，

$_SESSION['id'] = $row['login_id']

需要;

意外的变量

2 个答案: