:jQuery / Sizzle中的nth-of-type()?

时间:2010-01-19 12:20:38

标签: jquery jquery-selectors css-selectors selectors-api

令我感到惊讶的是Sizzle(jQuery使用的选择器引擎)带有内置:nth-child()选择器,但缺少:nth-of-type()选择器。

为了说明:nth-child():nth-of-type()之间的区别并说明问题,请考虑the following HTML document

<!doctype html>
<html>
 <head>
  <meta charset="utf-8">
  <title>:nth-of-type() in Sizzle/jQuery?</title>
  <style>
   body p:nth-of-type(2n) { background: red; }
  </style>
 </head>
 <body>
  <p>The following CSS is applied to this document:</p>
  <pre>body p:nth-of-type(2n) { background: red; }</pre>
  <p>This is paragraph #1.</p>
  <p>This is paragraph #2. (Should be matched.)</p>
  <p>This is paragraph #3.</p>
  <p>This is paragraph #4. (Should be matched.)</p>
  <div>This is not a paragraph, but a <code>div</code>.</div>
  <p>This is paragraph #5.</p>
  <p>This is paragraph #6. (Should be matched.)</p>
  <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script>
  <script>
   $(function() {
    // The following should give every second paragraph (those that had red backgrounds already after the CSS was applied) an orange background.
    // $('body p:nth-of-type(2n)').css('background', 'orange');
   });
  </script>
 </body>
</html>

由于Sizzle使用浏览器原生的querySelector()querySelectorAll()方法(如果已经存在Selectors API),因此$('body p:nth-child');之类的内容会课程工作。但它在旧版浏览器中不起作用,因为Sizzle没有这个选择器的回退方法。

是否可以轻松地将:nth-of-type()选择器添加到Sizzle,或者在jQuery中实现它(或许可以使用the built-in :nth-child() selector)? custom selector with parameters会很好。

3 个答案:

答案 0 :(得分:14)

/**
 * Return true to include current element
 * Return false to exclude current element
 */
$.expr[':']['nth-of-type'] = function(elem, i, match) {
    if (match[3].indexOf("n") === -1) return i + 1 == match[3];
    var parts = match[3].split("+");
    return (i + 1 - (parts[1] || 0)) % parseInt(parts[0], 10) === 0;
};

Test case - (检入IE或重命名选择器

您当然可以添加甚至&amp; 奇数

match[3] = match[3] == "even" ? "2n" : match[3] == "odd" ? "2n+1" : match[3];

答案 1 :(得分:4)

jQuery插件moreSelectors支持nth-of-type(以及许多其他选择器)。我建议使用它,或者只是实现一个只实现你需要的精确选择器的简单插件。您应该能够从那里复制粘贴代码。

快乐的黑客攻击!

答案 2 :(得分:1)

我不能假装知道如何实现nth-of-type,但jQuery确实提供了一种机制,您可以通过它创建自己的自定义选择器。

以下问题涉及自定义选择器,可能会为您提供有用的见解

What useful custom jQuery selectors have you written?