查询表达式中的语法错误(缺少运算符)'tbl_employee.emp_id = tbl_netpay.emp_id INNER JOIN tbl_gross ON tbl_employee.emp_id = tbl_gross.emp_ID INNER JOIN tbl_tax ON tbl_employee.emp_id - tbl_tax.emp_ID'。
SELECT tbl_employee.emp_ID,
tbl_employee.emp_name,
tbl_gross.BasicSalary,
tbl_gross.totalOT,
tbl_netpay.totalGross,
tbl_tax.totalLate,
tbl_tax.allowance,
tbl_tax.SSS,
tbl_tax.PhilHealth,
tbl_tax.GSIS,
tbl_tax.HDMF,
tbl_netpay.totalDeduc,
tbl_netpay.emp_ti,
tbl_netpay.emp_wt,
tbl_netpay.emp_np
FROM tbl_employee
INNER JOIN tbl_netpay ON tbl_employee.emp_id = tbl_netpay.emp_id
INNER JOIN tbl_gross ON tbl_employee.emp_id = tbl_gross.emp_ID
INNER JOIN tbl_tax ON tbl_employee.emp_id = tbl_tax.emp_ID;
我总是得到上面的错误。
答案 0 :(得分:87)
对于包含多个联接的查询,访问需要FROM
子句中的括号。试试这种方式......
FROM
((tbl_employee
INNER JOIN tbl_netpay
ON tbl_employee.emp_id = tbl_netpay.emp_id)
INNER JOIN tbl_gross
ON tbl_employee.emp_id = tbl_gross.emp_ID)
INNER JOIN tbl_tax
ON tbl_employee.emp_id = tbl_tax.emp_ID;
如果可能,请使用Access查询设计器设置联接。设计人员将根据需要添加括号以使数据库引擎保持满意。
答案 1 :(得分:7)
感谢HansUp的回答,这非常有用,而且很有效!
我发现在Access中有三种模式,你的是最好的,因为它适用于所有情况。
INNER JOIN,你的变种。我将其称为“关闭设置模式”。 可以将两个以上的表连接到同一个表,只有这种模式具有良好的性能。
SELECT C_Name, cr.P_FirstName+" "+cr.P_SurName AS ClassRepresentativ, cr2.P_FirstName+" "+cr2.P_SurName AS ClassRepresentativ2nd
FROM
((class
INNER JOIN person AS cr
ON class.C_P_ClassRep=cr.P_Nr
)
INNER JOIN person AS cr2
ON class.C_P_ClassRep2nd=cr2.P_Nr
)
INNER JOIN“链式设置模式”
SELECT C_Name, cr.P_FirstName+" "+cr.P_SurName AS ClassRepresentativ, cr2.P_FirstName+" "+cr2.P_SurName AS ClassRepresentativ2nd
FROM person AS cr
INNER JOIN ( class
INNER JOIN ( person AS cr2
) ON class.C_P_ClassRep2nd=cr2.P_Nr
) ON class.C_P_ClassRep=cr.P_Nr
;
与WHERE交叉加入
SELECT C_Name, cr.P_FirstName+" "+cr.P_SurName AS ClassRepresentativ, cr2.P_FirstName+" "+cr2.P_SurName AS ClassRepresentativ2nd
FROM class, person AS cr, person AS cr2
WHERE class.C_P_ClassRep=cr.P_Nr AND class.C_P_ClassRep2nd=cr2.P_Nr
;