我想在单个查询中加入join 2 select:
以下是两个查询。
SELECT player_id, SUM(score) score
FROM (
SELECT id_p1 player_id, score_p1 score
FROM matchs
UNION ALL
SELECT id_p2, score_p2
FROM matchs
) q
GROUP BY player_id
AND
SELECT player_id, SUM(score) score
FROM (
SELECT id_p1 player_id, score_p2 score
FROM matchs
UNION ALL
SELECT id_p2, score_p1
FROM matchs
) q
GROUP BY player_id
谢谢!
答案 0 :(得分:1)
试试这个
SELECT table1.player_id, table1.score score1, table2.score score2,
abs(table1.score - table2.score) difference
FROM (
SELECT player_id, SUM(score) score
FROM (
SELECT player1_id player_id, score_p1 score FROM matchs
UNION ALL
SELECT player2_id , score_p2 FROM matchs
) q GROUP BY player_id
) table1
INNER JOIN
(
SELECT player_id, SUM(score) score
FROM (
SELECT player1_id player_id, score_p2 score FROM matchs
UNION ALL
SELECT player2_id , score_p1 FROM matchs
) q GROUP BY player_id
) table2 ON table1.player_id = table2.player_id
<强> SQL Fiddle Demo 强>
答案 1 :(得分:0)
理想情况下,可以使用FULL JOIN
:
SELECT COALESCE(t1.player1_id, t2.player2_id)
SUM(COALESCE(t1.score_p1,0) + COALESCE(t2.score_p2,0))
FROM table_name t1
FULL JOIN table_name t2 ON t1.player1_id = t2.player2_id
GROUP BY COALESCE(t1.player1_id, t2.player2_id)
然而,遗憾的是MySQL没有对这种连接操作的原生支持。相反,可以通过在UNION
和LEFT JOIN
之间设置RIGHT JOIN
来模拟它,然后汇总:
SELECT p, SUM(s) FROM (
SELECT t1.player1_id p, SUM(t1.score_p1 + IFNULL(t2.score_p2,0)) s
FROM table_name t1
LEFT JOIN table_name t2 ON t1.player1_id = t2.player2_id
GROUP BY t1.player1_id
UNION
SELECT t2.player2_id, SUM(IFNULL(t1.score_p1,0) + t2.score_p2)
FROM table_name t1
RIGHT JOIN table_name t2 ON t1.player1_id = t2.player2_id
GROUP BY t2.player2_id
) t GROUP BY p
在sqlfiddle上查看。