的Clojure

Question

如何仅使用循环

来产生以下输出

iteration 1 = 54321 
iteration 2 = 43215
iteration 3 = 32145
iteration 4 = 21345 
iteration 5 = 12345

我能理解的语言是C ++，JavaScript，Php，PLSQL（最好是PlSql）

Answer 1

在C ++ 11中：由于你没有解释逻辑，我做最简单的^^：

int main () {
  const int numbers[5] = {54321, 43215, 32145, 21345, 12345};

  for (auto number : numbers) {
      std::cout << number << std::endl;
  }
    return 0;
}

Answer 2

您呈现的结果似乎是选择排序的效果。您必须实现以下算法：

For i = N downto 2
    Let b = index of the biggest element from 1 to i
    if b != i
        Exchange item b with item i

Answer 3

C ++

#include <iostream>
using namespace std;
int main(){
    int i, j;
    for(i=9; i>4; i--){
        for(j=5; j>=1; j--){
            cout<<( ( (i+j)%5 ) +1 );
        }
        cout<<endl;
    }
}

的JavaScript

<script type="text/javascript">
var i, j;
for(i=9; i>4; i--){
    for(j=5; j>=1; j--){
        document.write( ( (i+j)%5 ) +1 );
    }
    document.write("<br />");
}
</script>

Answer 4

的Clojure

由于这似乎是作业，我真的不适合给你一个你可以上交的答案 - 所以我会用稍微不同的语言给你答案，你可以翻译它：

(let [i [1 2 3 4 5]
      a [54321 43215 32145 21345 12345]]
  (doall (map #(println "Iteration " %1 " = " %2) i a)))

分享并享受。

Answer 5

PL SQL Block

declare
  v_string varchar2(5) := '54321';
begin
  for i in 1 .. length(v_string) loop
    dbms_output.put_line('iteration ' || i || ' = ' || v_string);
    v_string := substr('54321', 2) || substr('54321', 1, 1) ;
  end loop;
end;
/

Answer 6

似乎没人提到标准的C ++算法std :: rotate

const size_t N = 5;
int a[N] = { 5, 4, 3, 2, 1 };

for ( size_t i = N; i != 0; i-- )
{
    for ( int x : a ) std::cout << x;
    std::cout << std::endl;
    std::rotate( a, a + 1, a + i );
}

Answer 7

Please check this code. I think it will solve your query regarding iterations you require.Thanks

DECLARE
  v_var        VARCHAR2(100);
  v_num        NUMBER;
  v_chnge      VARCHAR2(100);
  v_finl_chnge VARCHAR2(100);
  v_frst_str   VARCHAR2(100);
BEGIN
  v_var:=trim('&enter');
  v_num:=LENGTH(v_var);
  dbms_output.put_line(LENGTH(v_var));
  FOR i IN 1..v_num
  LOOP
    v_frst_str  :=SUBSTR(v_var,-v_num,i);
    v_chnge     :=SUBSTR(v_var,i,v_num);
    v_finl_chnge:=(v_chnge||v_frst_str);
    dbms_output.put_line(SUBSTR(v_finl_chnge,-v_num,v_num));
  END LOOP;
END;

------------------------
OUTPUT
------------------------------
anonymous block completed
5
34562
45623
56234
62345
23456

如何通过循环实现欲望输出

7 个答案:

C ++

的JavaScript

的Clojure