Question

我试图通过PHP文件从AIR应用程序访问MySQL数据库但是当我尝试访问从页面返回的数据时，它会显示为未定义或HTML标记。我将PHP代码放在p标签之间，并打印出预期结果key1=value1&username=h（h是我数据库中的测试用户。）

AS3班级

    public class MySQLAccess {

        public var loader:URLLoader;
        public var result:URLVariables;
        public const url:String = "http://www.host.com/";
        private var req:URLRequest;
        public var vars:URLVariables;

        public function MySQLAccess() {
            result = new URLVariables();
            loader = new URLLoader();
            loader.dataFormat = URLLoaderDataFormat.VARIABLES;
            loader.addEventListener(Event.COMPLETE, onURLComplete);
            //loader.addEventListener(IOErrorEvent.IO_ERROR,ioerror);
            //loader.addEventListener(HTTPStatusEvent.HTTP_STATUS, httpStatus);
        }

        public function addNewUser(username:String, password:String, email:String) {
            req = new URLRequest(url + "registration.php");
            vars = new URLVariables();
            vars.username = username;
            vars.password = password;
            vars.email = email;
            req.data = vars;
            req.method = URLRequestMethod.POST;
            loader.load(req);
        }

        public function searchUser(username:String, email:String) {
            req = new URLRequest(url + "getUser.php");
            vars = new URLVariables();
            vars.username = username;
            vars.email = email;
            req.data = vars;
            req.method = URLRequestMethod.POST;
            loader.load(req);
        }

        public function onURLComplete(e:Event) {
            trace("Accessed " + this.url);
            result = e.target.data;
            trace("" + e.target.data.key1);
            trace (result.username);
        }

        /*public function ioerror(e:IOErrorEvent) {
            trace("Error: " + e.errorID);
        }

        public function httpStatus(e:HTTPStatusEvent) {
            trace(e.status);
        }*/
    }
}

PHP

    //if (isset($_POST[username], $_POST[email])) {
        //$result = mysqli_query($con, "select username from users where username = '$_POST[username]' or email = '$_POST[email]'");
    //}

    $result = mysqli_query($con, "select username from users where username = 'h'");

    print "key1=value1";
    while($row = mysqli_fetch_array($result)) {
          print '&username=' . $row['username'];
     }

    mysqli_close($con);
?>

Flash控制台中的输出（某些标记已省略）

Accessed http://www.host.com/
undefined
h</body>
</html><!-- www.serversfree.com Analytics Code -->

<script type="text/javascript" src="http://www.bugs3.com/ganalytics.js"></script>

<!-- End Of Analytics Code -->

Answer 1

啊我忘了为你回答这个问题。

function onURLComplete(e:Event):void 
{
    var loader2:URLLoader = URLLoader(e.target);
    var variables:URLVariables = new URLVariables(loader2.data);
    trace(variables.key1);
    trace(variables.username);
}

AS3 HTMLRequest使用PHP数据返回HTML标记

1 个答案: