我有一个带回归输出的矩阵,想要使用here提供的类似答案并使用以下代码命名第一列:
df1<-setNames(cbind(rownames(df), df, row.names = NULL),
c("pollutant", "Estimate" , "Std. Error" ,"t value" , "Pr(>|t|)" ))
然而,这并没有产生我想要的东西。通常我将数据保存为csv文件并重新导入,在这些情况下,第一列自动命名为“X”。
上面的代码有什么问题,如何命名此矩阵的第一列,避免长时间保存和导入文件?
以下提供的示例数据:
> dput(mydf)
structure(c(3.14803244479112, 0.00216192812492776, 0.000684290073147021,
0.0292623173688936, 0.0297132981713028, 0.00974078727655406,
0.00560338111861983, 0.0204778865914662, 0.0222708214105165,
0.0374599288412558, 0.0423851703062228, 0.00310423463278227,
0.000395577034883573, 0.0115743985421555, 0.0116695497549973,
0.0117671202864663, 0.0117449236915669, 0.0116767755856412, 0.011592495851043,
0.0134646435665112, 74.2720253816921, 0.696444818344823, 1.72985288023209,
2.52819334519339, 2.54622490114312, 0.827797034399079, 0.477089614693976,
1.753727854173, 1.9211412017467, 2.78209583909259, 0, 0.486174360549084,
0.0837024207196054, 0.0114878037421748, 0.0109115954666798, 0.407814812496389,
0.633313804135875, 0.0795226758181369, 0.0547561105194828, 0.00541595385956953
), .Dim = c(10L, 4L), .Dimnames = list(c("(Intercept)", "o3t_01",
"rh_01", "as.factor(dow)2", "as.factor(dow)3", "as.factor(dow)4",
"as.factor(dow)5", "as.factor(dow)6", "as.factor(dow)7", "as.factor(holiday)1"
), c("Estimate", "Std. Error", "t value", "Pr(>|t|)")))
答案 0 :(得分:3)
您必须使用data.frame
代替cbind
将不同类型的数据分配到一个结构中。
> data.frame(pollutant=rownames(df), df, row.names=NULL, check.names = FALSE)
pollutant Estimate Std. Error t value Pr(>|t|)
1 (Intercept) 3.1480324448 0.042385170 74.2720254 0.000000000
2 o3t_01 0.0021619281 0.003104235 0.6964448 0.486174361
3 rh_01 0.0006842901 0.000395577 1.7298529 0.083702421
4 as.factor(dow)2 0.0292623174 0.011574399 2.5281933 0.011487804
5 as.factor(dow)3 0.0297132982 0.011669550 2.5462249 0.010911595
6 as.factor(dow)4 0.0097407873 0.011767120 0.8277970 0.407814812
7 as.factor(dow)5 0.0056033811 0.011744924 0.4770896 0.633313804
8 as.factor(dow)6 0.0204778866 0.011676776 1.7537279 0.079522676
9 as.factor(dow)7 0.0222708214 0.011592496 1.9211412 0.054756111
10 as.factor(holiday)1 0.0374599288 0.013464644 2.7820958 0.005415954