Question

这是来自here的后续问题。但问题不同。

我有以下数组输出。

Array $events

Array
(
    [0] => Array
        (
            [day] => 17
            [eventContent] => event 1 of 17th
            [eventTitle] => 17th event 1
        )

    [1] => Array
        (
            [day] => 19
            [eventContent] => event 1 of 19th
            [eventTitle] => 19th event 1
        )

    [2] => Array
        (
            [day] => 05
            [eventContent] => event 1 of 5th
            [eventTitle] => 5th event 1
        )

    [3] => Array
        (
            [day] => 17
            [eventContent] => event 2 of 17th
            [eventTitle] => 17th event 2
        )

    [4] => Array
        (
            [day] => 19
            [eventContent] => event 2 of 19th
            [eventTitle] => 19th event 2
        )

    [5] => Array
        (
            [day] => 19
            [eventContent] => event 3 of 19th
            [eventTitle] => 19th event 3
        )

)

我想退出一天。

如果我使用它，它将获得1,2,3等。但我想要17,19等。

if(array_key_exists($day,$events)){...

能告诉我怎么做吗？

提前致谢。

- UPDATE -

我需要修改的原始视图。

if(array_key_exists($day,$events))
{

//adding the date_has_event class to the <td> and close it
echo ' class="date_has_event"> '.$day;
//adding the eventTitle and eventContent wrapped inside <span> & <li> to <ul>
echo '<div class="events"><ul>';?>
<?php foreach ($events as $event) : ?>
<li>
<span class="title"><?php echo $event['eventTitle']; ?></span>
<span class="desc"><?php echo $event['eventContent']; ?></span>
</li>
<?php endforeach; ?>

<?php                           
echo '</ul></div>';
}

Answer 1

试试这个：

$eventsByDay = array();
foreach ($events as $key => $event) {
    if (!isset($eventsByDay[$event['day']])) {
        $eventsByDay[$event['day']] = array();
    }
    $eventsByDay[$event['day']][] = $event;
}

$eventsByDay现在是一个数组，其中键是日期，值是相应事件的数组。

Answer 2

foreach ($events as $event) {
   echo $event['day'];
}

或者获得特定的一天：

echo $events[0]['day'];

Answer 3

问题是你想要做的......一些不同的方法：

eaxmple只需使用foreach打印它们：

foreach($array as $element) {
    echo $element['day']."\n";
}

或创建一个新数组，用array_map保存jsut：

function map_func($dat) {
    return $dat['day'];
}
$days = array_map('map_func', $array);

Answer 4

$events = array(...);
$days = array();

foreach($events as $event) {
  $day = $event['day'];
  $count = isset($days[$day]) ? $days[$day]++ : 1;

  $days[$day] = $count;
}

print_r($days);

上面的代码创建了一个新数组：[day] =＆gt;事件计数

Answer 5

<?php

class Event{
    protected $day;
    protected $eventContent;
    protected $eventTitle;

    public function __construct($day,$eventContent,$eventTitle){
        $this->day=$day;
        $this->eventContent=$eventContent;
        $this->eventTitle=$eventTitle;
    }

    public function getDay(){
        return $this->day;
    }
}

class EventContainer{
    protected $container=array();

    public function add(Event $NewEvent){
        $this->container[$NewEvent->getDay]=$NewEvent;
        return $this;
    }

    /**
     * You can make this one as comples as you want, and even add later a more complex index
     */
    public function search($day){
        return (isset($this->container[$day]))?$this->container[$day]:null;
    }

}


//IN THE BL CODE!

$Cont=new EventContainer;
$Conat->add(new Event(12,'aaa','bbb')
      ->add(new Event(18,'ccc','xxx')
      ->add(new Event(22,'fg','xerwrxx');

var_dump($Cont->search(18));

Answer 6

如果您使用＆gt;请尝试此操作php 5

$iterator = new RecursiveArrayIterator($array);

for($i=0;$<count($iterator);$i++)
{
// code here or 
echo $iterator[$i]["day"];

}

如何从PHP中的嵌套数组中提取数据？

6 个答案: