我正在创建一个带有spring security的spring mvc应用程序..但是当我在web.xml中添加安全过滤器时,它给了我没有bean命名的异常(Maven项目)
我的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="scala-spring-hibernate" version="2.5">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-context-data.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-context-web.xml,
/WEB-INF/spring-context-data.xml,
/WEB-INF/spring-security.xml
</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
<filter>
<filter-name>methodFilter</filter-name>
<filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>methodFilter</filter-name>
<url-pattern>*.html</url-pattern>
</filter-mapping>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping> <filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern> </filter-mapping>
<welcome-file-list>
<welcome-file>login.html</welcome-file>
</welcome-file-list>
</web-app>
答案 0 :(得分:0)
大多数情况下,您缺少创建springSecurityFilterChain bean所需的最小配置。
在文件spring-security.xml中,确保&lt; http&gt;使用Spring Security命名空间配置元素。