我有这样的表,
REPORT_ID USER_ID ACTION_TYPE ACTION_START
----------------- ----------- ----------- -----------------------
20122511549-621 621 OPEN 2012-02-05 11:05:49.000
20122511549-621 621 CLOSE 2012-02-19 10:53:28.000
20132121098-621 621 OPEN 2013-02-12 10:09:08.807
20132121098-621 621 ACCEPT 2013-02-12 11:16:17.167
20132121098-621 621 COMMENT 2013-02-12 12:20:17.167
20132121098-621 621 CLOSE 2013-03-22 16:20:17.167
201321814390-621 621 OPEN 2013-02-18 14:39:00.157
201322010148-707 707 OPEN 2013-02-20 10:01:48.693
201322010148-707 707 RETRIEVE 2013-10-29 13:22:05.017
我正在尝试的没有太大成功的是从上一行到当前行选择ACTION_START作为prev_action_start
条件:
当所有行的REPORT_ID = REPORT_ID时,除了ACTION_TYPE ='OPEN'时,当前行为prev_action_start应为ACTION_START 看起来像这样:
REPORT_ID USER_ID ACTION_TYPE ACTION_START prev_action_start
----------------- ----------- ----------- ----------------------- ------------------------
20122511549-621 621 OPEN 2012-02-05 11:05:49.000 2012-02-05 11:05:49.000
20122511549-621 621 CLOSE 2012-02-19 10:53:28.000 2012-02-05 11:05:49.000
20132121098-621 621 OPEN 2013-02-12 10:09:08.807 2013-02-12 10:09:08.807
20132121098-621 621 ACCEPT 2013-02-12 11:16:17.167 2013-02-12 10:09:08.807
20132121098-621 621 COMMENT 2013-02-12 12:20:17.167 2013-02-12 11:16:17.167
20132121098-621 621 CLOSE 2013-03-22 16:20:17.167 2013-02-12 12:20:17.167
201321814390-621 621 OPEN 2013-02-18 14:39:00.157 2013-02-18 14:39:00.157
201322010148-707 707 OPEN 2013-02-20 10:01:48.693 2013-02-20 10:01:48.693
201322010148-707 707 RETRIEVE 2013-10-29 13:22:05.017 2013-02-20 10:01:48.693
如果any1可以帮助我会感激吗?
答案 0 :(得分:3)
在SQL Server 2012中,您可以使用lag()
功能。在早期版本中,您需要执行显式连接或相关子查询。我发现后者最容易遵循:
select t.*,
(case when Action_Type = 'Open' then Action_Start else prev1
end) as prev_action_start
from (select t.*,
(select top 1 Action_Start
from table t2
where t2.ReportId = t.ReportId and
t2.Action_Start < t.Action_Start
order by Action_Start desc
) as prev1
from table t
) t;
您实际上可以将子查询放在case
语句中(消除子查询),但我认为将逻辑分成两部分会更清楚。