Question

我正在制定一些插入新客户的程序。这是我的代码：

CREATE OR REPLACE PROCEDURE ADD_CUST
(
 P_CUST_ID       CUST_INFO.CUST_ID%TYPE,
 P_CUST_F_NAME   CUST_INFO.CUST_F_NAME%TYPE,
 P_CUST_L_NAME   CUST_INFO.CUST_L_NAME%TYPE,
 P_CUST_ADDRESS  CUST_INFO.CUST_ADDRESS%TYPE,
 P_CITY          CUST_INFO.CITY%TYPE,
 P_STATE         CUST_INFO.STATE%TYPE,
 P_ZIP           CUST_INFO.ZIP%TYPE,
 P_PHONE         CUST_INFO.PHONE%TYPE
 )
IS
BEGIN
   INSERT INTO CUST_INFO (
   CUST_ID, CUST_F_NAME, CUST_L_NAME, CUST_ADDRESS, CITY,STATE, ZIP, PHONE) 
      VALUES (
   P_CUST_ID, P_CUST_F_NAME, P_CUST_L_NAME, P_CUST_ADDRESS, P_CITY, P_STATE, P_ZIP,P_PHONE
              )
END ADD_CUST;
/

这是我的cust_info表：

CREATE TABLE CUST_INFO
(
 CUST_ID       NUMBER(15),
 CUST_F_NAME   VARCHAR(20),
 CUST_L_NAME   VARCHAR(20),
 CUST_ADDRESS  VARCHAR(40),
 CITY          VARCHAR(30),
 STATE         VARCHAR(30),
 ZIP           NUMBER,
 PHONE         VARCHAR(12),
 PRIMARY KEY (CUST_ID)
 );

我收到的错误至少对我来说不是很有用。 LINE / COL ERROR

15/1 PL / SQL：忽略SQL语句 20/7 PL / SQL：ORA-00933：SQL命令未正确结束 20/19 PLS-00103：在期待时遇到符号“文件结束” 以下之一：（如果循环mod，则开始为goto声明结束异常退出 null pragma raise返回选择更新时使用＆LT;＆LT;继续关闭当前删除获取锁定 insert open rollback savepoint set sql execute commit forall 合并管道清除

谢谢。

Answer 1

     CREATE OR REPLACE PROCEDURE ADD_CUST
     (
      P_CUST_ID       CUST_INFO.CUST_ID%TYPE,
      P_CUST_F_NAME   CUST_INFO.CUST_F_NAME%TYPE,
      P_CUST_L_NAME   CUST_INFO.CUST_L_NAME%TYPE,
      P_CUST_ADDRESS  CUST_INFO.CUST_ADDRESS%TYPE,
      P_CITY          CUST_INFO.CITY%TYPE,
      P_STATE         CUST_INFO.STATE%TYPE,
      P_ZIP           CUST_INFO.ZIP%TYPE,
      P_PHONE         CUST_INFO.PHONE%TYPE
      )
      IS
      BEGIN

INSERT INTO CUST_INFO (
CUST_ID, CUST_F_NAME, CUST_L_NAME, CUST_ADDRESS, CITY,STATE, ZIP, PHONE) 
      VALUES (
P_CUST_ID, P_CUST_F_NAME, P_CUST_L_NAME, P_CUST_ADDRESS, P_CITY, P_STATE, P_ZIP,P_PHONE
             );
      END ADD_CUST;
      /

刚删除其间的括号，可能是复制粘贴问题;我相信休息的时间！

PLS-00103在一个程序中

1 个答案: