Question

我需要在C中的单词列表中搜索单词，并计算该单词的出现次数。

这是我到目前为止所尝试的内容：

{
    char *namePtr , *newnamePtr ; char  newname[1][8] ;
    int occurrence ;

    namePtr=&name[i];
    printf("enter the word you want to count : \n");
    scanf("%s",newname[1][8]);
    for(i=0; i< N ; i++)
    {
        if(strcmp(namePtr,newnamePtr)==0)
            occurrence++ ;
        else
            if(strcmp(namePtr,newnamePtr)!=0)
                printf("this word does not exist in  the list!");
    }
    printf("the occurrence  of this word is %d",occurrence) ;
}

如何计算单词列表中单词的出现次数？

Answer 1

如果您想要计算子字符串，可以使用以下代码：

int main(void)
{
    char text[] = "foo bar foo bar foo";
    char word[] = "foo";
    char *p;
    int occurences = 0;

    for (p = text; (p = strstr(p, word)) != NULL; p += sizeof(word) - 1)
    {
        occurences++;
    }

    printf("Occurences of %s = %d\n", word, occurrences);
}

Answer 2

要搜索由分隔符分隔的句子/单词列表中的单词，您可以使用strstr()和循环来查找该单词的所有匹配项。

样本可能是这样的。

//strstr returns a pointer to first occurrence of the string found else NULL

do
{
   p=strstr(str1,str2);
   if(p) count++;

}while(p);

还有一个several other algorithms来实现同样的目标。

Answer 3

#include <stdio.h>
#include <string.h>

#define N 10

char *name[N] = {
    "the", "name", "pointer", "the", "count",
    "word", "want", "to", "count", "exist"
};

int main(){
    char *namePtr , *newnamePtr ;
    char  newname[8];
    int i, occurrence = 0;

    printf("enter the word you want to count : \n");
    scanf("%s", newname);
    newnamePtr = newname;
    for(i=0; i< N ; i++){
        namePtr = name[i];
        if(strcmp(namePtr, newnamePtr)==0)//strcmp(name[i], newname)
            occurrence++;
    }
    if(occurrence==0)
        printf("this word does not exist in  the list!");
    else
        printf("the occurrence  of this word is %d", occurrence);

    return 0;
}

Answer 4

这是一个简化版本：

char newname[80];
int occurrence = 0;

printf("enter the word you want to count : \n");
scanf("%s", newname);
for (i = 0; i < N ; ++i)
{
    if( strcmp(name[i], newname) == 0 ) // access list directly
        ++occurrence;
    else // no need to check the inverse of the condition
        printf("this word does not exist in the list!");
}

printf("the occurrence  of this word is %d", occurrence) ;

要计算子字符串（部分匹配），请替换：

    if( strcmp(name[i], newname) == 0 ) // access list directly

带

    if( strstr(name[i], newname) != NULL ) // access list directly

如何计算单词列表中单词的实例

4 个答案: