Question

我目前正在编写一个SQL脚本，在数据库中进行了一些更改，我希望用户确认每个步骤的结果。

代码：

SET ECHO ON
SET AUTOCOMMIT OFF
SET EXITCOMMIT OFF
-- make changes
update plan_table
set statement_id = '3'
where statement_id = '2';
-- check if correct
select statement_id from plan_table;
-- ask confirmation
ACCEPT response CHAR DEFAULT 'n' PROMPT 'Result ok? - y/n: ';
  if lower(&response) = 'y' then (
    update plan_table
    set statement_id = '4'
    where statement_id = '3';
    -- check if correct
    select statement_id from plan_table;
    -- ask confirmation
    ACCEPT response CHAR DEFAULT 'n' PROMPT 'Result ok? - y/n: ';
     if lower(&response) = 'y' then commit;
     else rollback;
     end if;
  )
  else rollback;
  end if;
/
exit;

更改有效，但我在尝试验证时总是收到错误（接受响应部分）：

SQL>     -- ask confirmation
SQL>     ACCEPT response CHAR DEFAULT 'n' PROMPT 'Result ok? - y/n: ';
Result ok? - y/n: SQL>    if lower(&response) = 'y' then commit;
SP2-0734: unknown command beginning "if lower(&..." - rest of line ignored.
SQL>      else rollback;
SP2-0734: unknown command beginning "else rollb..." - rest of line ignored.
SQL>      end if;
SP2-0042: unknown command "end if" - rest of line ignored.
SQL>   )
SP2-0042: unknown command ")" - rest of line ignored.
SP2-0044: For a list of known commands enter HELP
and to leave enter EXIT.
SQL>   else rollback;
SP2-0734: unknown command beginning "else rollb..." - rest of line ignored.
SQL>   end if;
SP2-0042: unknown command "end if" - rest of line ignored.
SQL> /

谁能告诉我我做错了什么？

使用案例时出现

错误：

Enter value for userreply: old   7: case &userReply when 'y' then exit commit
new   7: case y when 'y' then exit commit
ACCEPT userReply PROMPT 'Result ok? - y/n: '
       *
ERROR at line 6:
ORA-06550: line 6, column 8:
PLS-00103: Encountered the symbol "USERREPLY" when expecting one of the
following:
:= . ( @ % ;

由于

Answer 1

好的，作为一项有趣的练习，我已经在SQL脚本中实现了您的要求。我不推荐这种方法，它过于复杂而且坦率地说有点傻！最好的方法是在您选择的开发环境中编写应用程序 - 可以是APEX，Forms，ASP，Pro * C，......

我必须创建一些脚本：

1）do_update.sql：

-- make changes
update plan_table
set statement_id = '&1.'
where statement_id = '&2.';

-- check if correct
select statement_id from plan_table;

-- ask confirmation
ACCEPT response CHAR DEFAULT 'n' PROMPT 'Result ok? - y/n: ';

-- Based on confirmation set prefix to 'do' or 'dont'
set term off verify off

column prefix new_value prefix

select case upper('&response.')
       when 'Y' then 'do'
       else 'dont'
       end as prefix
from dual;

set term on

2）dont_update.sql：

-- don't make changes

3）do_commit.sql：

commit;

4）dont_commit.sql：

rollback;

5）main.sql：

@@do_update 3 2
@@&prefix._update 4 3
@@&prefix._commit

现在在SQL Plus中运行main.sql：

SQL> @main

1 row updated.


STATEMENT_ID
------------------------------
1
3
3

Result ok? - y/n: y

2 rows updated.


STATEMENT_ID
------------------------------
1
4
4

Result ok? - y/n: y

Commit complete.

当然，这只是基于您的简单示例。对于更现实的情况，脚本的数量会更大。我会不这样做！

Answer 2

首先，您使用pl / sql语法编写。 sql中没有条件子句。尝试纠正语法并开始用pl / sql语法编写。据我所知，逻辑很清楚。

如何询问用户是否要使用batch / sql文件提交/回滚更改

2 个答案: