Question

Line = "A[0x04] Va   [0xf]

如何将这些行拆分为包含0x04和0xf的两个变量？

尝试解决方案：

for line in sys.stdin:
    line.strip("[]").split

Answer 1

我会使用re.findall：

>>> from re import findall
>>> Line = "A[0x04] Va   [0xf] "
>>> findall("\[([^\]]*)\]", Line)
['0x04', '0xf']
>>> x,y = findall("\[([^\]]*)\]", Line)
>>> x
'0x04'
>>> y
'0xf'
>>>

以下是正则表达式模式的细分：

\[        # [
([^\]]*)  # Capture group to get zero or more characters that are not ]
\]        # ]

Answer 2

import re
re.findall("\[[^\]]*\]", Line)

Answer 3

使用列表理解：

>>> Line = "A[0x04] Va   [0xf]"
>>> [x.partition(']')[0] for x in Line.split('[') if ']' in x]
['0x04', '0xf']

Answer 4

In [36]: %paste
answer = []
take = False
line = "A[0x04] Va   [0xf] "
start = 0
for i,char in enumerate(line):
    if not take:
        if char == '[' :
            take = True
            start = i+1
    else:
        if char == ']':
            take = False
            answer.append(line[start:i])

## -- End pasted text --

In [37]: answer
Out[37]: ['0x04', '0xf']

在Python中用括号中的值去除的优雅方法

4 个答案: