Question

我在函数中有一个For循环，如下所示：

int fnSearch(int arnSalaries [10][2], int nSalary, char cFound)
{
    int nRow, nCol;

    printf("Please enter the Salary to find the Employee ID : ");
    scanf("%d", &nSalary);

    for(nRow = 0; nRow < 10; nRow++)
    {
        if(nSalary == arnSalaries[nRow][1])
        {
            printf("\%d found - Employee ID matching that salary is: %d\n", 
                nSalary, arnSalaries[nRow][0]);
            cFound = 'Y';
            //nRow = 10; /* This is to break out of the loop */
        }
    }

    if(cFound == 'N')
    {
        printf("Sorry, that salary does not match an employee\n");
    }

    return cFound;
}

当我输入“10000”等薪水时，输出如下：

10000 found - Employee ID matching that salary is: 21
10000 found - Employee ID matching that salary is: 23

如何更改代码，使其显示如下内容：

10000 found - Employee ID(s) matching that salary is/are: 21, 23

编辑：我不是在寻找任何要编写的代码 - 只是在正确的方向上暗示我应该考虑解决这个问题

Answer 1

在循环之前打印除id号之外的所有内容。在循环内部，只打印id号。在循环之后，打印换行符。

Answer 2

希望这可以帮到你：

int fnSearch(int arnSalaries [10][2], int nSalary, char cFound)
{
int nRow, nCol, i = 0;
int foundIndex[] = int[10]; //10 or number of rows of arnSalaries
printf("Please enter the Salary to find the Employee ID : ");
scanf("%d", &nSalary);

for(nRow = 0; nRow < 10; nRow++)
{
    if(nSalary == arnSalaries[nRow][1])
    {
        cFound = 'Y';
        foundIndex[i++] = nRow;
    }
}

if(cFound == 'N')
    printf("Sorry, that salary does not match an employee\n");
else
{
    printf("\%d found - Employee ID matching that salary is/are :",nSalary);
    for(i = 0;i<sizeof(foundIndex);i++)
        printf("%d,",arnSalaries[foundIndex[i]][0])
}

return cFound;
}

请更正一些语法错误。

输出2值一行输入循环 - C

2 个答案: