我的SQL查询是
SELECT DISTINCT a.user_login, a.user_email, c.domain
FROM wp_users a
JOIN wp_usermeta b ON a.id = b.user_id
JOIN wp_blogs c ON b.meta_value = c.site_id
WHERE user_login != SUBSTRING_INDEX( user_email, '@', 1 )
LIMIT 0 , 100
结果如下所示
user_login user_email domain
ff ff@asd.com a.b.c
ff ff@asd.com f.g.h
aa aa@asd.com a.b.c
aa aa@asd.com b.n.m
我需要结果像
user_login user_email domain
ff ff@asd.com a.b.c,f.g.h
aa aa@asd.com a.b.c,b.n.m
我是sql的新手,我无法确定以这种方式得到结果的意思。
答案 0 :(得分:2)
您正在寻找GROUP_CONCAT()
SELECT DISTINCT a.user_login, a.user_email, GROUP_CONCAT(c.domain)
FROM wp_users a
JOIN wp_usermeta b ON a.id = b.user_id
JOIN wp_blogs c ON b.meta_value = c.site_id
WHERE user_login != SUBSTRING_INDEX( user_email, '@', 1 )
GROUP BY user_login
LIMIT 0 , 100