Question

我的编码需要帮助。我想将RGB值（十进制）转换为二进制值。但每当应该有＆＃39; 0＆＃39;在二进制值前面，结果没有显示＆＃39; 0＆＃39; 0位。

示例：decimal = 94，binary = 0101 1110.但我的结果显示为101 1110。

我想分析我的程序的所有二进制位，图像隐写分析。如果没有足够的8位二进制位，我担心会出错。

这些是我的编码：

public class getPixelData 
{
private static final double bitPerColor = 4.0;

public getPixelData()
{

}

public int[] getPixelData(BufferedImage img, int w, int h) throws IOException
{
    int argb = img.getRGB(w, h);
    int rgb[] = new int[]
    {
        (argb >> 16) & 0xff, //red
        (argb >>  8) & 0xff, //green
        (argb      ) & 0xff  //blue
    };

    int red = rgb[0];
    int green = rgb[1]; //RGB Value in Decimal
    int blue = rgb[2];

    System.out.println("\nRGBValue in Decimal --> " + "\nRed: " + red + " Green: " + green + " Blue: " + blue);

    //Convert each channel RGB to Hexadecimal value
    String rHex = Integer.toHexString((int)(red));
    String gHex = Integer.toHexString((int)(green));
    String bHex = Integer.toHexString((int)(blue));

    System.out.println("\nRGBValue in Hexa --> " + "\nRed Green Blue " + rHex + gHex + bHex);

    //Convert each channel RGB to binary
    String r4bit = Integer.toBinaryString((int)(red));
    String g4bit = Integer.toBinaryString((int)(green));
    String b4bit = Integer.toBinaryString((int)(blue));

    //Convert concatonate 0's in front to get desired bit count
    int rDifference = (int)bitPerColor - r4bit.length();
    int gDifference = (int)bitPerColor - g4bit.length();
    int bDifference = (int)bitPerColor - b4bit.length();

    //this code should work but i guess it isn't
    for (int i = rDifference; i > 0; i--)
    {
        r4bit = "0" + r4bit;
    }

    for (int i = gDifference; i > 0; i--)
    {
        g4bit = "0" + g4bit;
    }

    for (int i = bDifference; i > 0; i--)
    {
        b4bit = "0" + b4bit;
    }


    System.out.println("\nRGB Value in binary (Red) is: " + r4bit);
    System.out.println("RGB Value in binary (Green) is: " + g4bit);
    System.out.println("RGB Value in binary (Blue) is: " + b4bit);

    return rgb;
    }
    }

我应该在这里添加什么？仅供参考，我还是Java语言的新手。如果我在这里犯了任何错误，请纠正我。

由于

Answer 1

你不需要用力量来划分吗？

float power = Math.pow(2, 4);
String r4bit = Integer.toBinaryString((int)(red/power));
String g4bit = Integer.toBinaryString((int)(green/power));
String b4bit = Integer.toBinaryString((int)(blue/power));

Answer 2

你需要自己用0填充它们。如果我找到你，这是类似的问题： Binary format of an integer

从十进制转换为二进制后，二进制值没有显示足够的8位

2 个答案: