我想获得一个唯一名称列表以及一个行计数列,以便它看起来像这样:
1 wilford building
2 oxford center
3 williams place
我需要那里的独特,所以我只获得每个建筑物名称一次。
SELECT R.RowNum,
R.COLUMN_NAME
FROM
(
SELECT ROW_NUMBER() OVER (PARTITION BY buildingName
ORDER BY buildingName ) AS RowNum,
DISTINCT buildingName AS COLUMN_NAME
FROM cityStatus
) AS R
但是,事实并非如此。
是否可以将DISTINCT
与ROW_NUMBER()
一起使用?
答案 0 :(得分:5)
SELECT
buildingName,
ROW_NUMBER() OVER(ORDER BY buildingName) AS RowNum
FROM cityStatus
GROUP BY buildingName
答案 1 :(得分:2)
先做清楚的事了:
SELECT
row_number() over(partition by buildingName ORDER BY buildingName ) AS RowNum
,COLUMN_NAME
from (
select
DISTINCT buildingName AS COLUMN_NAME
FROM cityStatus
) as cityStatus