Question

我有一个clientid和用户名，我希望他们都用套接字发送。

 client.userid = userid;
 client.username = username;
 client.emit('onconnected', { id: client.userid, name: client.username });

我试过这个例子，但它似乎不起作用

Answer 1

你可以试试这个

io.sockets.on('connection', function (socket) {
  socket.on('event_name', function(data) {
      // you can try one of these three options

      // this is used to send to all connecting sockets
      io.sockets.emit('eventToClient', { id: userid, name: username });
      // this is used to send to all connecting sockets except the sending one
      socket.broadcast.emit('eventToClient',{ id: userid, name: username });
      // this is used to the sending one
      socket.emit('eventToClient',{ id: userid, name: username });
  }
}

并在客户端

 socket.on('eventToClient',function(data) {
    // do something with data
       var id = data.id
       var name = data.name // here, it should be data.name instead of data.username

 });

Answer 2

尝试整体发送对象：

$('form').submit(function(){      
var loginDetails={  
    userid : userid,  
    username : username  
    };  
client.emit('sentMsg',loginDetails);  
}

Answer 3

您应该将对象传递给套接字事件。

在服务器端：

socket.emit('your-event', { name: 'Whatever', age: 18 })

在客户端：

socket.on('your-event', ({ name, age }) => {
    // name: Whatever
    // age: 18
})

如何使用Socket.io在一个消息中发送两个变量？

3 个答案: