我正在制作一个简单的购物车应用程序。主页面显示产品列表。当您单击产品名称时,它会将您带到显示该产品信息的页面。现在,它没有显示任何东西。这是我的代码:
<?php
$sql = "SELECT product_id, image_path, name, description, price FROM products;";
$result = mysql_query($sql);
while(list($product_id, $image_path, $name, $description, $price) = mysql_fetch_row($result)) {
echo "<tr>";
echo "<td><img src=$image_path height=200 width=160 border=1px /></td>";
echo "<td><b><a href=\"getprod.php?product=" .
$product_id['product_id'] . "\">$name</a></b><br/ >";
echo "$description<br/ >";
echo "$$price<br/ >";
echo "<input type='button' value='Add to Cart' onclick='addtocart'/>";
echo "</tr>";
}
?>
我的productInfo方法应该显示我的信息:
function productInfo($product_id) {
global $conn;
if($product_id) {
$sql= "SELECT product_id,image_path, name, description, price " .
"FROM products WHERE product_id = " . $product_id; " .
$result= mysql_query($sql, $conn) or
die('Could not find product info: ' . mysql_error());
while(list($product_id, $image_path, $name, $description, $price) = mysql_fetch_row($result)) {
echo "<td><img src=$image_path height=200 width=160 border=1px /></td>";
echo "<td><b><a href=\"getprod.php?product=" .
$product_id['product_id'] . "\">$name</a></b><br/ >";
echo "$long_description<br/ >";
echo "$$price<br/ >";
echo "<input type='button' value='Add to Cart' onclick='addtocart'/>";
}
}
}
非常感谢任何正确方向的帮助或推动!
答案 0 :(得分:1)
当您使用list()获取$product_id
时,在您的while循环中,更改:
echo "<td><b><a href=\"getprod.php?product=" .
$product_id['product_id'] . "\">$name</a></b><br/ >";
到
echo "<td><b><a href=\"getprod.php?product=" .
$product_id . "\">$name</a></b><br/ >";
答案 1 :(得分:0)
您只是从数据库表中选择“product_id”。如果要使用list()命令,则应指定要返回的内容:
$sql= "SELECT product_id, image_path, name, description, price FROM products WHERE product_id = " . $product_id;
此外,如果您的product_id未在数据库中列为整数,而是text或varchar,您可能希望在产品ID周围加上引号
$sql= "SELECT product_id, image_path, name, description, price FROM products WHERE product_id = \"$product_id\"";