好的,所以我想将多个文件连接成一个。问题是最终文件是空的。我想知道如何在没有覆盖的情况下将内容写入文件等等。这是我的代码。 提前谢谢!
void concatenate()
{
fstream fileToConcatenate, result;
unsigned numberOfFiles = 0;
char fileName[MAX], finalFileName[MAX];
puts("Please tell me how many files you want to concatenate.");
cin >> numberOfFiles;
puts("Please tell me data for the resulted file.\n*Hint: full path followed by the file name.\n*E.g:C:\\Users\\IoanaAlexandra\\test.txt");
cin >> finalFileName;
result.open(finalFileName, ios::out|ios::ate);
for (unsigned i = 0; i < numberOfFiles; i++)
{
switch (i)
{
case 0:puts("Please tell me the file data for the first file to be concatenated.\n*Hint: full path followed by the file name.\n*E.g:C:\\Users\\IoanaAlexandra\\test.txt"); break;
case 1:puts("Please tell me the file data for the second file."); break;
case 2:puts("Please tell me the file data for the third file."); break;
default:cout << "Please tell me the file data for the " << i << "th file."; break;
}
cin >> fileName;
fileToConcatenate.open(fileName, ios::in);
if (result.is_open())
{
if (fileToConcatenate.is_open())
{
result << fileToConcatenate.rdbuf();
}
else
{
puts("The file you are trying to concatenate from doesn't exist!Try again!");
concatenate();
}
}
else
{
puts("The result file could not be created! Try again!");
concatenate();
}
}
fileToConcatenate.close();
result.close();
}
答案 0 :(得分:3)
从循环外部移除result.open()
并尝试将代码更改为:
fileToConcatenate.open(fileName, ios::in);
if (fileToConcatenate.is_open())
{
// open output file
result.open(finalFileName, ios::out|ios::ate);
// you should check so the output file really was opened correctly here
result << fileToConcatenate.rdbuf();
// close the input file
fileToConcatenate.close();
// close output file
result.close();
}
else
{
puts("The file you are trying to concatenate from doesn't exist!Try again!");
concatenate();
}
如果fileToConcatenate
已被打开,您也应关闭concatenate()
,然后再次致电{{1}}。