我正在研究这个扑克游戏项目，我一直坚持如何打印出卡片类型以及功能结束时的默认“对不起，你输了”。我不确定我的代码是否正确，我将不胜感激任何类型的帮助。
基本上，我的程序需要打印出来：
[A Spades, 10 Spades, Q Spades, J Spades, K Spades]
Royal Flush!
--------------------------------------------------
[9 Spades, 10 Spades, Q Spades, J Spades, K Spades]
Straight Flush!
--------------------------------------------------
但我的程序只打印出来：
[A Spades, 10 Spades, Q Spades, J Spades, K Spades]
我在打印类型（皇家同花顺部分）时遇到问题。
/**
* Check current currentHand using multipliers and goodHandTypes arrays Must
* print yourHandType (default is "Sorry, you lost") at the end of function.
* This can be checked by testCheckHands() and main() method.
*/
private void checkHands() {
// implement this method!
List<Card> sortedHand = new ArrayList<Card>(currentHand);
Collections.sort(sortedHand, new Comparator<Card>() {
@Override
public int compare(Card card1, Card card2) {
int rank1 = card1.getRank();
int rank2 = card2.getRank();
if (rank1 > rank2) {
return 1;
}
if (rank1 < rank2){
return -1;
}
return 0;
}
}
int rank = 0;
String ranks;
if (isRoyalPair() == true) {
rank = 1;
if (isTwoPair() == true) {
rank = 2;
}
if (isThreeOfAKind() == true) {
rank = 3;
}
if (isStraight() == true) {
rank = 4;
}
if (isFlush() == true) {
rank = 5;
}
if (isFullHouse() == true) {
rank = 6;
}
if (isFourOfAKind() == true) {
rank = 7;
}
if (isStraightFlush() == true) {
rank = 8;
}
if (isRoyalFlush() == true) {
rank = 9;
}
}
rank -= 1;
if (rank < 0) {
ranks = "Sorry, you lost!";
} else {
ranks = goodHandTypes[rank];
}
System.out.println("" + ranks);
switch (ranks) {
case "1":
this.balance += (this.bet * multipliers[0]);
break;
case "2":
this.balance += (this.bet * multipliers[1]);
break;
case "3":
this.balance += (this.bet * multipliers[2]);
break;
case "4":
this.balance += (this.bet * multipliers[3]);
break;
case "5":
this.balance += (this.bet * multipliers[4]);
break;
case "6":
this.balance += (this.bet * multipliers[5]);
break;
case "7":
this.balance += (this.bet * multipliers[6]);
break;
case "8":
this.balance += (this.bet * multipliers[7]);
break;
case "9":
this.balance += (this.bet * multipliers[8]);
break;
default:
break;
}
}
我已经拥有了他们的所有方法，我只需要帮助找到打印它们的方法：
private boolean isStraight() {
for (int i = 0; i < numberOfCards; i++) {
if (currentHand.get(i).getRank() != currentHand.get(i + 1).getRank()) {
return false;
}
}
return true;
}
private boolean isFlush() {
for (int i = 0; i < numberOfCards; i++) {
if (currentHand.get(i).getSuit() != currentHand.get(i + 1).getSuit()) {
return false;
}
}
return true;
}
private boolean isStraightFlush() {
if (isStraight() == true && isFlush() == true) {
return true;
}
return false;
}
private boolean isRoyalFlush() {
if (isFlush() == false || isStraight() == false) {
return false;
} else {
if (currentHand.get(0).getRank() == 10) {
return true;
}
return false;
}
}
private boolean isFourOfAKind() {
//runs thru the hand for exactly 4 matches
for (int i = 0; i < numberOfCards - 1; i++) {
int counter = 0;
for (int y = i + 1; y < numberOfCards; y++) {
if (currentHand.get(i).getRank() == currentHand.get(0).getRank()) {
counter++;
}
}
if (counter == 4) {
return true;
} else {
return false;
}
}
return false;
}
private boolean isFullHouse() {
if (isThreeOfAKind() == true && isOnePair() == true) {
return true;
} else {
return false;
}
}
private boolean isThreeOfAKind() {
//matches three
for (int i = 0; i < numberOfCards; i++) {
int counter = 0;
for (int y = 0; y < numberOfCards; y++) {
if (currentHand.get(i).getRank() == currentHand.get(y).getRank()) {
counter++;
for (int x = 0; x < numberOfCards; x++) {
if (currentHand.get(i).getRank() == currentHand.get(x).getRank()) {
counter++;
}
}
if (counter == 3) {
return true;
} else {
return false;
}
}
private boolean isTwoPair() {
//check if it is four of a kind or two pair))
if (isFourOfAKind() == true) {
return false;
}
int numberOfPair = 0;
int counter = 1;
return false;
}
private boolean isOnePair() {
return false;
}
public boolean isRoyalPair() {
if (isOnePair() == false && isTwoPair() == false && isThreeOfAKind() == false && isFourOfAKind() == false
&& isFullHouse() == false && isRoyalFlush() == false && isFlush() == false && isStraight() == false && isStraightFlush() == false) {
return true;
}
return false;
}
答案 0 :(得分：1)
看起来checkHands()没有被调用！
稍后...
Collections.sort(sortedHand, new Comparator<Card>() {
@Override
public int compare(Card card1, Card card2) {
int rank1 = card1.getRank();
int rank2 = card2.getRank();
if (rank1 > rank2) {
return 1;
}
if (rank1 < rank2){
return -1;
}
return 0;
}
} /* Should be ); here */
int rank = 0;
...
不太重要
if (isRoyalPair() == true) {
rank = 1;
if (isTwoPair() == true) {
rank = 2;
}
...
手牌（一套5张牌）不应该有排名，（至少如果你要调用每张牌的排名，则不会有排名）。双手应该有一个名字，或者更确切地说是String，以获得这些牌的最佳牌局。例如，
String type = "none";
...
if (isRoyalFlush()) type = "Royal Flush!!!!!";
//or if(isRoyalFlush()) type = goodHandTypes[9];
请注意，没有必要将其检查的内容true与true进行比较。有几种方法可以实现逻辑的可读性和/或更少的输入和其他问题，但是这个顺序的9 if语句是合理的。而且他们每个只执行一个语句，所以你可以不用括号。