我从h2 build in database
中选择条目的方法@Transactional(readOnly=true)
public static Result view() {
List<MedicalIncidents> data = JPA.em()
.createNativeQuery("SELECT * FROM MedicalIncident")
//.createQuery("Select m from MedicalIncident m")
.getResultList();
System.out.println(data);
我觉得它有效，因为我在数据库中的那个表中有两个条目：
但是System.out.println（data）在plaay console中返回：
[[Ljava.lang.Object;@70a0c9be, [Ljava.lang.Object;@4c1d12b6]
但它应该通过模型名称返回此对象，例如：computer-database-jpa：
[models.Computer@214c6fde, models.Computer@63728eb3, models.Computer@75f6bcc6, models.Computer@19e3a7ab, models.Computer@3114d8d4, models.Computer@4fa75f78, models.Computer@756ce822, models.Computer@40fc4c68, models.Computer@73fc612c, models.Computer@3e4fcb31]
所以我觉得它有问题。请帮忙
如何使用该对象将它们与模型类绑定，如下例所示： 计算机数据库-jpa http://www.playframework.com/documentation/2.2.x/Samples
这条代码的痕迹：
List<MedicalIncidents> data = JPA.em().createNativeQuery("SELECT * FROM MedicalIncident", MedicalIncident.class)
.getResultList();
System.out.println(data);
STACK TRACE
[info] play - Application started (Dev)
[error] o.h.e.j.s.SqlExceptionHelper - Kolumna "_ebean_intercept" nie istnieje
Column "_ebean_intercept" not found [42122-172]
[error] play - Cannot invoke the action, eventually got an error: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query
[error] application -
! @6ghb6iadj - Internal server error, for (GET) [/incydent_medyczny/podglad] ->
play.api.Application$$anon$1: Execution exception[[PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query]]
at play.api.Application$class.handleError(Application.scala:293) ~[play_2.10.jar:2.2.1]
at play.api.DefaultApplication.handleError(Application.scala:399) [play_2.10.jar:2.2.1]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
at scala.Option.map(Option.scala:145) [scala-library.jar:na]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2.applyOrElse(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1387) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1310) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.ejb.QueryImpl.getResultList(QueryImpl.java:277) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at controllers.MedicalIncidents.view(MedicalIncidents.java:68) ~[na:na]
at Routes$$anonfun$routes$1$$anonfun$applyOrElse$3$$anonfun$apply$3.apply(routes_routing.scala:81) ~[na:na]
at Routes$$anonfun$routes$1$$anonfun$applyOrElse$3$$anonfun$apply$3.apply(routes_routing.scala:81) ~[na:na]
Caused by: org.hibernate.exception.SQLGrammarException: could not execute query
at org.hibernate.exception.internal.SQLStateConversionDelegate.convert(SQLStateConversionDelegate.java:123) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.loader.Loader.doList(Loader.java:2529) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.loader.Loader.doList(Loader.java:2512) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2342) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
Caused by: org.h2.jdbc.JdbcSQLException: Kolumna "_ebean_intercept" nie istnieje
Column "_ebean_intercept" not found [42122-172]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:329) ~[h2.jar:1.3.172]
at org.h2.message.DbException.get(DbException.java:169) ~[h2.jar:1.3.172]
at org.h2.message.DbException.get(DbException.java:146) ~[h2.jar:1.3.172]
at org.h2.jdbc.JdbcResultSet.getColumnIndex(JdbcResultSet.java:3047) ~[h2.jar:1.3.172]
at org.h2.jdbc.JdbcResultSet.get(JdbcResultSet.java:3133) ~[h2.jar:1.3.172]
at org.h2.jdbc.JdbcResultSet.getBytes(JdbcResultSet.java:1042) ~[h2.jar:1.3.172]
models.MedicalIncydent.class
package models;
import java.util.*;
import javax.persistence.*;
import javax.persistence.Entity;
import javax.validation.*;
import play.data.validation.Constraints;
import play.data.validation.Constraints.*;
import play.api.db.*;
import play.db.jpa.*;
import javax.persistence.EntityManager;
@Entity
public class MedicalIncident {
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
public int id;
@Constraints.Required
public String month;
@Constraints.Required
public String place;
@Constraints.Required
public String unit;
@Constraints.Required
public String incident_type;
@Constraints.Required
public int age;
/**
* Insert this new incident submission.
*/
public void toDataBase() {
// persist object - add to entity manager
JPA.em().merge(this);
JPA.em().persist(this);
}
}
答案 0 :(得分：0)
libraryDependencies ++ = Seq（
javaJdbc，
javaJpa，
缓存，
javaws的，
＆＃34; org.hibernate作为＆＃34; ％＆＃34; hibernate-entitymanager＆＃34; ％＆＃34; 4.3.9.Final＆＃34;）
重新启动激活器后，请确保键入＆＃34; clean＆＃34;命令
public class Application extends Controller {
@Transactional
public static Result index() {
Query query = JPA.em().createNativeQuery("select * from fetched_results limit 10", FetchedResults.class);
List<FetchedResults> lst = query.getResultList();
System.out.println(lst.get(0).name);
return ok(test.render("Your new application is ready."));
}
}