我正在尝试使用部分href xpath扫描HTML表格中的行,并使用该行的其他列值执行进一步测试。
<div id = "blah">
<table>
<tr>
<td><a href="afile?key=HONDA">link</a></td>
<td>29 33 485</td>
<td>45.2934,00 EUR</td>
</tr>
<tr>
<td><a href="afile?key=HONDA">link</a></td>
<td>22 93 485</td>
<td>38.336.934,123 EUR</td>
</tr>
<tr>
<td><a href="afile?key=something_else">link</a></td>
<td>394 27 3844</td>
<td>3.485,2839 EUR</td>
</tr>
</table>
</div>
在cucumber-jvm步骤定义中,我很容易像下面那样执行这个(我更习惯使用Ruby)
@Given("^if there are...$")
public void if_there_are...() throws Throwable {
...
...
baseTable = driver.findElement(By.id("blah"));
tblRows = baseTable.findElements(By.tagName("tr"));
for(WebElement row : tblRows) {
if (row.findElements(By.xpath(".//a[contains(@href,'key=HONDA')]")).size() > 0) {
List<WebElement> col = row.findElements(By.tagName("td"));
tblData dummyThing = new tblData();
dummyThing.col1 = col.get(0).getText();
dummyThing.col2 = col.get(1).getText();
dummyThing.col3 = col.get(2).getText();
dummyThing.col4 = col.get(3).getText();
dummyThings.add(dummyThing);
}
}
我在这里一无所知
page.find('#blah').all('tr').each { |row|
# if row matches xpath then grab that complete row
# so that other column values can be verified
# I am clueless from here
row.find('td').each do { |c|
}
page.find('#blah').all('tr').find(:xpath, ".//a[contains(@href,'key=HONDA')]").each { |r|
#we got the row that matches xpath, let us do something
}
}
答案 0 :(得分:15)
我认为你要这样做:
page.all('#blah tr').each do |tr|
next unless tr.has_selector?('a[href*="HONDA"]')
# Do stuff with trs that meet the href requirement
puts tr.text
end
#=> link 29 33 485 45.2934,00 EUR
#=> link 22 93 485 38.336.934,123 EUR
这基本上说:
您还可以使用xpath将上述内容折叠为单个语句。但是,我不认为它是可读的:
page.all(:xpath, '//div[@id="blah"]//tr[.//a[contains(@href, "HONDA")]]').each do |tr|
# Do stuff with trs that meet the href requirement
puts tr.text
end
#=> link 29 33 485 45.2934,00 EUR
#=> link 22 93 485 38.336.934,123 EUR
以下是如何检查每个匹配行的链接网址和列值的示例:
page.all('#blah tr').each do |tr|
next unless tr.has_selector?('a[href*="HONDA"]')
# Do stuff with trs that meet the href requirement
href = tr.find('a')['href']
column_value_1 = tr.all('td')[1].text
column_value_2 = tr.all('td')[2].text
puts href, column_value_1, column_value_2
end
#=> file:///C:/Scripts/Misc/Programming/Capybara/afile?key=HONDA
#=> 29 33 485
#=> 45.2934,00 EUR
#=> file:///C:/Scripts/Misc/Programming/Capybara/afile?key=HONDA
#=> 22 93 485
#=> 38.336.934,123 EUR