我编写了这个粗略的最小堆代码,它是我在C ++中编写的类似程序的翻译。我认为我必须错误地使用切片,因为go代码比C ++代码慢。在Go中插入和删除100,000个整数大约需要19秒,但在C ++中只需要1.73秒。有人可以提供一些建议吗?或者Go比C ++慢得多?我在Linux下计算这样的代码:“time ./pqgo -n 100000 -d 100000> / dev / null”。这是代码:
package main
import (
"fmt"
"time"
"math/rand"
"flag"
)
func insert( key int, lPq []int) []int {
lPq = append( lPq[:], key )
i := len(lPq) - 1
for ; i > 1 && lPq[ i/2 ] > lPq[i] ; {
lTemp := lPq[ i/2 ]
lPq[ i/2 ] = lPq[i]
lPq[i] = lTemp
i = i / 2
}
return lPq
}
func delete_min( lPq []int) (int, []int) {
lRetVal := lPq[1]
lPq[1] = lPq[ len(lPq)-1 ]
lPq = lPq[0:len(lPq)-1 ]
k := 1
for ; 2*k <= len(lPq); {
j := 2*k
if k < len(lPq) && lPq[j] > lPq[j+1] {
j++
}
if lPq[k] <= lPq[j] {
break
}
lTemp := lPq[k]
lPq[k] = lPq[j]
lPq[j] = lTemp
}
return lRetVal, lPq
}
func main() {
var lPq []int
lPq = append(lPq[:], -9999)
var ip *int = flag.Int("n", 8, "help message")
var ip2 *int = flag.Int("d", 8, "help message2")
flag.Parse()
lNum := *ip
fmt.Printf( "lNum= %d\n", lNum)
lPq = insert( 17, lPq[:] );
lPq = insert( 19, lPq[:] );
lPq = insert( 9, lPq[:] );
lPq = insert( 4 , lPq[:]);
lPq = insert ( 12, lPq[:] );
rand.Seed(time.Now().UnixNano())
for i := 0; i < lNum; i++ {
lKey := rand.Intn( 4*lNum )
lPq = insert(lKey, lPq[:])
}
fmt.Printf("pq.size = %d\n", len(lPq) )
lPrintTo := len(lPq)
if lPrintTo > 64 {
lPrintTo = 64
}
var num int
for _, num = range lPq[0:lPrintTo] {
fmt.Printf( "%d ", num)
}
fmt.Println("");
var lMin int
for index := 1; index < 3; index++ {
lMin, lPq = delete_min( lPq[:] )
fmt.Printf( "lMin = %d\n", lMin)
for _, num = range lPq[0:lPrintTo] {
fmt.Printf( "%d ", num)
}
fmt.Println("");
}
lPq = insert( 3, lPq[:] );
lPq = insert( 4, lPq[:] );
lPq = insert( 1, lPq[:] );
lPq = insert( 8, lPq[:] );
lPq = insert( 20, lPq[:] );
lPq = insert( 21, lPq[:] );
lPq = insert( 6, lPq[:] );
lPq = insert ( 11, lPq[:] );
lNumToDelete := len( lPq )
lNumToDelete = *ip2
for index := 1; index < lNumToDelete-1; index++ {
lMin, lPq = delete_min( lPq[:] )
lPrintTo = len(lPq)
if lPrintTo > 64 {
lPrintTo = 64
}
fmt.Printf("lPrintTo = %d\n",lPrintTo )
fmt.Printf("pq.size = %d\n", len(lPq) )
for _, num = range lPq[0:lPrintTo] {
fmt.Printf( "%d ", num)
}
fmt.Println("");
}
}
// gccgo -Og -I/devserv-home/rspikol/include -o pqgo pq.go -L/devserv-home/rspikol/lib
答案 0 :(得分:4)
您的C ++版本是否会生成相同数量的输出?
最后一个循环运行lNumToDelete
(100,000)次,并在每次迭代时从队列中输出最多64个值。这是很多输出,格式化和写出需要时间,即使它是/dev/null
。
在删除循环中注释掉fmt.Printf()
调用使得程序运行得更快。
其他一些建议:
fmt.Printf("a = %d\n", b)
可以替换为fmt.Println("a =", b)
lPq[:]
可以替换为lPq