我已将xml文档导入SQL Server,我现在正尝试将各个部分导入到不同的表中。当我使用下面的查询时,它只返回一行hotel_facilities,我需要使用hotel_ref返回所有hotel_facilities。
DECLARE @Details xml
SET @Details = '<hotels>
<hotel>
<hotel_ref>105</hotel_ref>
<hotel_facilities>
<id>2</id>
<name>Disabled Facilities</name>
<id>4</id>
<name>24 Hour Reception</name>
<id>12</id>
<name>Restaurant</name>
</hotel_facilities>
</hotel>
</hotels>'
SELECT tab.col.value('../hotel_ref[1]','varchar(100)') AS 'hotel_ref',
tab.col.value('./id[1]','varchar(100)') AS 'HotelFacilityID',
tab.col.value('./name[1]','varchar(100)') AS 'HotelFacilityName'
FROM @Details.nodes('//hotels/hotel/hotel_facilities') AS tab(col)
答案 0 :(得分:2)
您的XML结构有点滑稽 - <hotel_facilities>
不包含您可以枚举的适当“子实体”......
如果您的设施被包裹在<facility>....</facility>
元素中,您可以轻松枚举。
<hotel_facilities>
<facility>
<id>2</id>
<name>Disabled Facilities</name>
</facility>
<facility>
<id>4</id>
<name>24 Hour Reception</name>
</facility>
<facility>
<id>12</id>
<name>Restaurant</name>
</facility>
</hotel_facilities>
但是根据您目前的设置,我认为您很难找到一个好的解决方案......
答案 1 :(得分:0)
我同意marc_s XML没有很好的架构。
我能得到的最接近的是:
SELECT tab.col.value('./hotel_ref[1]','varchar(100)') AS 'hotel_ref',
fac.value('(.)[1]','varchar(100)') AS 'HotelFacilityID',
ROWID=IDENTITY(int,1,1)
into #facilitiesid
FROM @Details.nodes('/hotels/hotel') AS tab(col)
cross apply col.nodes('.//id') a(fac)
SELECT tab.col.value('../hotel_ref[1]','varchar(100)') AS 'hotel_ref',
fac.value('(.)[1]','varchar(100)') AS 'HotelFacilityName',
ROWID=IDENTITY(int,1,1)
into #facilitiesnames
FROM @Details.nodes('//hotels/hotel/hotel_facilities') AS tab(col)
cross apply col.nodes('.//name') a(fac)
select i.hotel_ref, HotelFacilityID, HotelFacilityName
from #facilitiesid i
inner join #facilitiesnames n
on i.rowid = n.rowid